所以我想繪製一個圓弧並圍繞它的圓形端點放一個圓,但由於四捨五入到最近的像素而產生問題。這在一些情況下可見,但並非全部情況。Java Graphics2D浮點準確drawOval的替代?
有沒有一種方法可以使用浮點和抗鋸齒來消除這個舍入誤差?
您可以運行此代碼來查看問題。爲了清晰起見,我繪製了長度爲0的弧(顯示爲大點)而不是全弧。
import java.awt.*;
import javax.swing.*;
public class Example extends JFrame {
private int CENTER = 200;
private static int WINDOW = 400;
private int LEFT = 50;
private int TOP = 50;
private int DIM = 300;
private int DIAMETER = 26;
public Example() {
super();
}
public void paint (Graphics g) {
Graphics2D g2 = (Graphics2D) g;
g2.setRenderingHint(RenderingHints.KEY_ANTIALIASING, RenderingHints.VALUE_ANTIALIAS_ON);
g2.setStroke(new BasicStroke(16, BasicStroke.CAP_ROUND, BasicStroke.JOIN_MITER));
g2.setColor(new Color(0, 0, 255));
g2.drawArc(LEFT, TOP, DIM, DIM, 0, 0);
g2.drawArc(LEFT, TOP, DIM, DIM, 32, 0);
g2.drawArc(LEFT, TOP, DIM, DIM, 115, 0);
g2.drawArc(LEFT, TOP, DIM, DIM, 200, 0);
g2.drawArc(LEFT, TOP, DIM, DIM, 331, 0);
this.drawCircle(g2, 0);
this.drawCircle(g2, 32);
this.drawCircle(g2, 115);
this.drawCircle(g2, 200);
this.drawCircle(g2, 331);
g2.setStroke(new BasicStroke(1));
g2.setColor(new Color(0, 0, 0));
g2.drawLine(0, CENTER, DIM * 2, CENTER);
g2.drawLine(CENTER, 0, CENTER, DIM * 2);
}
private void drawCircle(Graphics2D g, int angle) {
g.setStroke(new BasicStroke(3));
g.setColor(new Color(0, 0, 255));
g.drawOval(
Math.round(CENTER + (float)(Math.cos(Math.toRadians(angle)) * (DIM/2)) - DIAMETER/2),
Math.round(CENTER - (float)(Math.sin(Math.toRadians(angle)) * (DIM/2)) - DIAMETER/2),
DIAMETER,
DIAMETER
);
}
public static void main (String args[]) {
Example e = new Example();
e.setSize(WINDOW, WINDOW);
e.setVisible(true);
e.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
}
}
['Ellipse2D'](https://docs.oracle.com/javase/8/docs/api/java/awt/geom/Ellipse2D.html)? – trashgod
如果你有三個方格連續你有一個明確的中心 - 如果你有四個方塊連續你沒有一個明確的中心 - 但如果你相信魔術繼續antialiasing等 – gpasch
@trashgod你搖滾。這加上'RenderingHints.VALUE_STROKE_PURE'完美地排列了一切。謝謝! – thedarklord47