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我正在嘗試找到橢圓和線之間的交點,但似乎無法這樣做。我嘗試了兩種方法,一種是通過嘗試找到LineString和LinearRing之間的交集,如下面的代碼所示,但沒有從中得到任何可用的值。其中的一個問題,是elipse總是會偏離中心,並在一個小的或大角度查找橢圓和線之間的交點
# -*- coding: utf-8 -*-
"""
Created on Mon Aug 19 17:38:55 2013
@author: adudchenko
"""
from pylab import *
import numpy as np
from shapely.geometry.polygon import LinearRing
from shapely.geometry import LineString
def ellipse_polyline(ellipses, n=100):
t = np.linspace(0, 2*np.pi, n, endpoint=False)
st = np.sin(t)
ct = np.cos(t)
result = []
for x0, y0, a, b, angle in ellipses:
angle = np.deg2rad(angle)
sa = np.sin(angle)
ca = np.cos(angle)
p = np.empty((n, 2))
p[:, 0] = x0 + a * ca * ct - b * sa * st
p[:, 1] = y0 + a * sa * ct + b * ca * st
result.append(p)
return result
def intersections(a, line):
ea = LinearRing(a)
eb = LinearRing(b)
mp = ea.intersection(eb)
print mp
x = [p.x for p in mp]
y = [p.y for p in mp]
return x, y
ellipses = [(1, 1, 2, 1, 45), (2, 0.5, 5, 1.5, -30)]
a, b = ellipse_polyline(ellipses)
line=LineString([[0,0],[4,4]])
x, y = intersections(a, line)
figure()
plot(x, y, "o")
plot(a[:,0], a[:,1])
plot(b[:,0], b[:,1])
show()
我使用fsolve如實施例波紋管也嘗試過,但它找到了錯誤的交叉點(或實際上一個錯點。
from pylab import *
from scipy.optimize import fsolve
import numpy as np
def ellipse_polyline(ellipses, n=100):
t = np.linspace(0, 2*np.pi, n, endpoint=False)
st = np.sin(t)
ct = np.cos(t)
result = []
for x0, y0, a, b, angle in ellipses:
angle = np.deg2rad(angle)
sa = np.sin(angle)
ca = np.cos(angle)
p = np.empty((n, 2))
p[:, 0] = x0 + a * ca * np.cos(t) - b * sa * np.sin(t)
p[:, 1] = y0 + a * sa * np.cos(t) + b * ca * np.sin(t)
result.append(p)
return result
def ellipse_line(txy):
t,x,y=txy
x0, y0, a, b, angle,m,lb=1, 1, 2, 1, 45,0.5,0
sa = np.sin(angle)
ca = np.cos(angle)
return (x0 + a * ca * np.cos(t) - b * sa * np.sin(t)-x,y0 + a * sa * np.cos(t) + b * ca * np.sin(t)-y,m*x+lb-y)
a,b= ellipse_polyline([(1, 1, 2, 1, 45), (2, 0.5, 5, 1.5, -30)])
t,y,x=fsolve(ellipse_line,(0,0,0))
print t,y,x
#print a[:,0]
m=0.5
bl=0
xl,yl=[],[]
for i in range(10):
xl.append(i)
yl.append(m*i+bl)
figure()
plot(x, y, "o")
plot(a[:,0], a[:,1])
plot(xl,yl)
任何幫助將appriceated?
似乎是完全適合http://math.stackexchange.com/ –
不是真的我想到一個問題。假設這不能直接解析,所以你需要一個數值方法,在這種情況下,這是發佈的正確地方。否則math.stackexchange.com是要走的路。 – usethedeathstar
@usethedeathstar ...好點!我沒有這樣想過...... –