我有一個小問題。我試圖在連接到arduino uno的4x4鍵盤的16x2 LCD屏幕上顯示字符。當我按下鍵盤按鈕時,相應的字符在串行監視器上成功打印,但不是dsplay。 我還應該提到,在查找字符的ASCII表之後,LCD上打印的錯誤字符對應於重複的ASCII字符,即按1鍵打印1111 1111,而另一個鍵可能打印對應於ASCII 1011的字符1011.基本上是從右下角到左上角的ascii表中的字符。另外,當我按下某個鍵時,它會在串行監視器上打印一次,但在LCD上多次打印。 我會在下面發佈我的代碼,並鏈接到我正在使用的鍵盤和LCD屏蔽。當我在顯示屏上打印字符/文字時,最後一個注意事項與鍵盤無關,因此它們打印的很好。16X2 LCD屏蔽與4x4矩陣鍵盤
代碼:
#include <Keypad.h>
#include <LiquidCrystal.h> // initialize the library with the numbers of the
LiquidCrystal lcd(8, 9, 4, 5, 6, 7);
const byte ROWS = 4; //four rows
const byte COLS = 4; //four columns
char hexaKeys[ROWS][COLS] = {
{'1','2','3','A'},
{'4','5','6','B'}, //define the cymbols on the buttons of the keypads
{'7','8','9','C'},
{'*','0','#','D'}
};
byte rowPins[ROWS] = {13, 12, 11, 10}; //connect to the row pinouts of the keypad
byte colPins[COLS] = {9, 8, 7, 6}; //connect to the column pinouts of the keypad
Keypad customKeypad = Keypad(makeKeymap(hexaKeys), rowPins, colPins, ROWS, COLS); //initialize an instance of class NewKeypad
void setup()
{
lcd.begin(16, 2);
Serial.begin(9600);
}
void loop()
{
char customKey = customKeypad.getKey();
if (customKey)
{
//lcd.setCursor(1,1);
lcd.print(customKey);
delay(500);
Serial.print(customKey);
}
}
LCD屏蔽: http://www.maplin.co.uk/p/16x2-lcd-shield-for-arduino-n07dh
鍵盤: https://www.coolcomponents.co.uk/sealed-membrane-4-4-button-pad-with-sticker.html
感謝,希望有人可以提供幫助。
我不確定你的問題在這裏。你想問我們什麼? – duskwuff
你是什麼意思?我問是否有人知道爲什麼在LCD上打印錯誤的字符,但在串行監視器上顯示正確的字符... – Davidgasp