轉換迭代次數，以在有限的範圍（等的週數天）

Question

我需要一個迭代數轉換成一系列的1和7

$y = keepInRange(1, 7, $i) 

結果輸入之間

- >輸出被期待作爲遵循

• 1 - > 1
• ...
• 7 - > 7
• 8 - > 1
• 9 - > 2
• ...
• 14 - > 7
• 15 - > 1

我已經嘗試了以下沒有成功：

min(7, max(1, $numberToStr[$i])) (all output 1) 
$y = $i % 7 (all outputs 0, Edit: this was a mistake by me, its the solution when +1 is added.) 

Answer 1

試試這個

<?php 
$num = 15; 
$res= $num%7; 
if($res == 0) 
{ 
    echo "7"; 
} 
else 
{ 
    echo $res; 
} 

https://3v4l.org/dDGs3

我希望這將是有益的

Answer 2

嘗試：

$day_of_week = $num <= 7 ? $num : $num % 7; 

演示：

for($num=1; $num<25; $num++) { 
    $day_of_week = $num <= 7 ? $num : $num % 7; 
    echo '<p>'.$num.': '.$day_of_week.'</p>'; 
} 

Demo in JS。