計數像素值bmp到像素值C++

Question

我拍了一張位圖圖像，並從其中拉出了R，G，B的整數，用於指定的一行像素。將int轉換爲一個字符串，以便我可以打印我的6種特定顏色。我無法弄清楚如何用int來做到這一點。

問題 我能夠將行0-184（對應於該行中的像素）作爲順序數據1234 ...或顏色紅色，紅色，紅色，黑色，黑色，灰色......打印出來。

但是，我需要計算像/相同的顏色，顯示相似顏色的總和，並重置計數器，直到該顏色再次出現，然後重新計算。我認爲如果還是其他人會這樣做，但不是很完美。這可能是我的代碼結構導致了一個問題？

所以我的願望是：

5 red, 
10 black, 
2 red, 
1 gray, 

等......

這裏是我的代碼，我是初學者所以批評我的知識的缺乏，讓我可以好好學學。

#include <iostream> 
#include <sstream> 
#include <string> 
#include "EasyBMP.h" 
#include "EasyBMP_BMP.h" 
#include "EasyBMP_DataStructures.h" 
#include "EasyBMP_VariousBMPutilities.h" 

//Conversion and comparison function 
void calculate(int i, int x, int p); 

int main(int argc, const char * argv[]) 
{ 

BMP Image; 
Image.ReadFromFile("BMP GOES HERE 24bit"); 

std::cout << "Image Height and Width: " << Image.TellHeight() << " x " << Image.TellWidth() << std::endl; 

std::cout << "Enter your row: "; 

int pixX = 0; 
std::cin >> pixX; 

//Set getpixel to top of row 
int pixY = 0; 

for(pixY = 0; pixY < Image.TellHeight() ; pixY++) 
{ 
    std::cout << "Pixel: " << pixY + 1; 

    RGBApixel Temp = Image.GetPixel(pixX,pixY); 

    //Array to store pixel color ints 
    int pixy[3]; 
    pixy[0] = Temp.Red; 
    pixy[1] = Temp.Green; 
    pixy[2] = Temp.Blue; 

    calculate(pixy[0], pixy[1], pixy[2]); 
} 

return 0; 
} 


void calculate(int rnum, int gnum, int bnum) 
{ 

//String which will contain the result 
std::string result; 

//Stream used for the conversion 
std::ostringstream convert; 

//Insert the textual representation of 'Number' in the characters in the stream 
convert << rnum;     

convert << gnum; 

convert << bnum; 

// set 'Result' to the contents of the stream 
result = convert.str();  

// compare result to my given value 
if (result == "25500") 
{ 
    std::cout << " RED " << std::endl; 
} 
if (result == "255255255") 
{ 
    std::cout << " WHITE " << std::endl; 
} 
if (result == "000") 
{ 
    std::cout << " BLACK" << std::endl; 
} 
if (result == "148148148") 
{ 
    std::cout << " GRAY " << std::endl; 
} 
if (result == "267326") 
{ 
    std::cout << " GREEN " << std::endl; 
} 
if (result == "2551260") 
{ 
    std::cout << " ORANGE " << std::endl; 
} 
} 

以下是工作代碼。請注意，如果您使用它，我的圖片只有6種特定顏色。要更改打印輸出，必須根據需要修改switch語句。

#include <iostream> 
#include <vector> 
#include "EasyBMP.h"  
#include "EasyBMP_BMP.h" 
#include "EasyBMP_DataStructures.h" 
#include "EasyBMP_VariousBMPutilities.h" 

long toRGB(long red, long grn, long blu); 


int main(int argc, const char * argv[]) 
{ 

BMP Image; 
Image.ReadFromFile("Your BMP HERE"); 

std::cout << "Image Height and Width: " << Image.TellHeight() << " x " << Image.TellWidth() << std::endl; 

std::cout << "Enter your row: "; 

int pixX = 0; 
std::cin >> pixX; 
if (pixX != 0)        //Subtract one from input if not 0, image starts at 0,0 
{ 
    pixX -= 1; 
} 

long pop = 0; 
long pop1 = 0; 

RGBApixel current = Image.GetPixel(pixX,0); 

long pixy1[3];          //Array to store pixel color ints 
pixy1[0] = current.Red; 
pixy1[1] = current.Green; 
pixy1[2] = current.Blue; 

pop1 = toRGB(pixy1[0], pixy1[1], pixy1[2]); 


int count = 0; 
for(int pixY = 0; pixY < Image.TellHeight() ; pixY++) 
{ 
    RGBApixel Temp = Image.GetPixel(pixX,pixY); 

    long pixy[3];          //Array to store pixel color ints 
    pixy[0] = Temp.Red; 
    pixy[1] = Temp.Green; 
    pixy[2] = Temp.Blue; 

    pop = toRGB(pixy[0], pixy[1], pixy[2]); 

    if (pop == pop1) 
    { 
     count++; 
    } 
    else 
    { 
     switch (pop1) { 
      case 0: 
       std::cout << "(" << count << ")\t" << "BLACK\n" << std::endl; 
       break; 
      case 16711680: 
       std::cout << "(" << count << ")\t" << "RED\n" << std::endl; 
       break; 
      case 9737364: 
       std::cout << "(" << count << ")\t" << "GRAY\n" << std::endl; 
       break; 
      case 16777215: 
       std::cout << "(" << count << ")\t" << "WHITE\n" << std::endl; 
       break; 
      case 1722650: 
       std::cout << "(" << count << ")\t" << "GREEN\n" << std::endl; 
       break; 
      case 16743936: 
       std::cout << "(" << count << ")\t" << "ORANGE\n" << std::endl; 
       break; 
      default: 
       std::cout << " !!!NO Specified COLOR For!!! " << pop1 << std::endl; 
       break; 
     } 

     pop1 = pop;          //Reset the count and current  color 
     count = 1; 
    } 
} 
    if (count > 0)          //Returns last color and count 
    { 
     switch (pop1) { 
      case 0: 
       std::cout << "(" << count << ")\t" << "BLACK\n" << std::endl; 
       break; 
      case 16711680: 
       std::cout << "(" << count << ")\t" << "RED\n" << std::endl; 
       break; 
      case 9737364: 
       std::cout << "(" << count << ")\t" << "GRAY\n" << std::endl; 
       break; 
      case 16777215: 
       std::cout << "(" << count << ")\t" << "WHITE\n" << std::endl; 
       break; 
      case 1722650: 
       std::cout << "(" << count << ")\t" << "GREEN\n" << std::endl; 
       break; 
      case 16743936: 
       std::cout << "(" << count << ")\t" << "ORANGE\n" << std::endl; 
       break; 
      default: 
       std::cout << " !!!NO Specified COLOR For!!! " << pop1 << std::endl; 
       break; 
    } 
} 

return 0; 
} 

long toRGB(long a, long b, long c)       //Function to convert R, G, B  values to unique value 
{ 
long color = 0; 
color |= (a & 255) << 16; 
color |= (b & 255) << 8; 
color |= (c & 255); 

return color; 
} 

Answer 1

我之前並沒有真正理解你的問題，所以我寫了一個更適合你的問題的新答案。

我認爲你可以得到你想要的東西像這樣的東西（修改代碼）：

RGBApixel current = Image.GetPixel(pixX,0); 
int count = 0; 
for(pixY = 0; pixY < Image.TellHeight() ; pixY++) 
{ 
    RGBApixel Temp = Image.GetPixel(pixX,pixY); 
    if (Temp == current) 
    { 
     count++; 
    } 
    else 
    { 
     // same-color sequence ended 
     // Add code here to print out current color and count 
     --- your output code ---- 

     // now reset the count and current color 
     current = Temp; 
     count = 1; 
    } 
} 

// Now just print out the last sequence 
if (count > 0) 
{ 
    --- your output code here again --- 
}  

有一件事我不知道是怎麼回事，如果在所有的==經營者爲RGBApixel定義。如果它沒有被定義，或者根據它們的顏色看起來並不相同，只需編寫一個函數，如pixelsAreEqual(RBGApixel p1, RGBApixel p2)，它需要兩個像素，如果它們具有相同的RGB值，則返回true。

Answer 2

有很多不同的方法可以完成計算給定顏色的像素數目。如果您感興趣的顏色列表很短，您可以創建一個大小等於初始化爲全0的顏色數的數組，然後編寫一個函數，該函數根據傳遞的顏色返回該數組的索引它（例如，紅色= 0，白色= 1，以任意順序;常量可能是跟蹤它的一個好方法），然後循環遍歷調用每個函數的像素並在給定索引處遞增數組。

這很簡單，但非常不雅。