SQL，如何從兩個不同的查詢中總結兩個總和

Question

我想在兩種不同的條件下獲取同一個變量的總和。只是想知道是否有辦法將這些加在一起。查詢的細節並不太相關。基本上只是試圖拿第一筆款項，並添加第二筆款項。

例如 -

首先查詢：

select sum(amt_tot) 
    from agbgift, aprdclb 
    where agbgift_id = '1' and agbgift_id = aprdclb_id 

第二個查詢：

select sum(amt_tot) 
    from agbgift, aprxref, aprdclb where 
    aprxref_id = '1' and 
    agbgift_id = aprxref_xref_id and 
    aprxref_id = aprdclb_id and 
    xref_code in ('SPS','BUS','ORG','OWN','FDN'); 

最終的結果我找的是 '第一個查詢點心' +「第二個查詢總和'

Answer 1

使用子句可以輕鬆實現，如果使用不起作用，可以在from子句中使用別名

with b ( select sum(amt_tot) as bsum 
    from agbgift, aprxref, aprdclb where 
    aprxref_id = '1' and 
    agbgift_id = aprxref_xref_id and 
    aprxref_id = aprdclb_id and 
    xref_code in ('SPS','BUS','ORG','OWN','FDN')) 
, a (select sum(amt_tot) asum 
    from agbgift, aprdclb 
    where agbgift_id = '1' and agbgift_id = aprdclb_id ) 
select a.asum + b.bsum 
from a, b 

這是真的在這種情況下：

select a.asum + b.bsum 
from (select sum(amt_tot) asum 
    from agbgift, aprdclb 
    where agbgift_id = '1' and agbgift_id = aprdclb_id) as a, 
    ( select sum(amt_tot) as bsum 
    from agbgift, aprxref, aprdclb where 
    aprxref_id = '1' and 
    agbgift_id = aprxref_xref_id and 
    aprxref_id = aprdclb_id and 
    xref_code in ('SPS','BUS','ORG','OWN','FDN')) as b 

Answer 2

在這種情況下，它是這樣簡單：

SELECT 
/* Query 1 (in parentheses) */ 
(select sum(amt_tot) 
    from agbgift, aprdclb 
    where agbgift_id = '1' and agbgift_id = aprdclb_id) 

    + /* plus */ 

/* Query 2 (also in parentheses) */ 
    (select sum(amt_tot) 
    from agbgift, aprxref, aprdclb where 
    aprxref_id = '1' and 
    agbgift_id = aprxref_xref_id and 
    aprxref_id = aprdclb_id and 
    xref_code in ('SPS','BUS','ORG','OWN','FDN'))