建立電話簿搜索矢量使用地圖庫

Question

目前即時創建一個簡單的電話簿。搜索矢量時遇到問題。當我需要搜索接近名稱的字符串時，它只能讓我在目錄中搜索確切的鍵。例如，當我搜索「汽車」時，它會聲明它不在目錄中，當它應該拉起卡爾，德里克和卡爾大衛。請幫忙謝謝。

#include <string> 
#include <map> 
#include <vector> 
#include <ostream> 
#include <iostream> 

int main() 
{ 
std::map<std::string, std::vector <std::string> > directory; 

directory["Carr"].push_back("Derek 916-667-6761"); 
directory["Carr"].push_back("David 916-667-6766"); 
directory["Mcfadden"].push_back("Darren 510-667-0000"); 
directory["Streater"].push_back("Rod 510-667-0001"); 
directory["Jones"].push_back("James 510-667-0020"); 
directory["Mack"].push_back("Khalil 707-557-6700"); 
directory["Woodson"].push_back("Charles 707-557-0061"); 
directory["Tuck"].push_back("Justin 707-557-6001"); 
directory["Moore"].push_back("Sio 415-600-5551"); 
directory["Roach"].push_back("Nick 415-600-4461"); 
directory["Woodson"].push_back("Rod 415-600-4441"); 

std::string str; 
int yesno; 
std::cout <<"Would you like to search a name in the phone directory?(yes=1, no=0)" <<std::endl; 
std::cin>>yesno; 
while (yesno==1) 
{ 
    std::cout << "Enter name you would like to find: "; 
    std::cin >> str; 

    std::map<std::string, std::vector <std::string> >::iterator p; 

    p = directory.find(str); 
    if(p != directory.end()) 
    { 
     std::string key = p->first; 
     std::vector<std::string> names = p->second; 

     for (int i = 0; i < names.size(); ++i) 
     std::cout << key << " " << names[i] << std::endl; 

    } 
    else 
    { 
     std::cout << "Name not in phone directory.\n"; 
    } 
    std::cout <<"Do you have another name you would like to look up?(yes=1, no=0)"<<std::endl; 
    std::cin>>yesno; 
    } 
    system("pause"); 
    return 0; 
    } 

Answer 1

這是計算機科學的一個重要領域，它與C++ STL（至少現在）沒有任何關係。

更多信息請參閱here。