從2個表

Question

選擇不同的酒吧foo的

比方說，我有兩個表：

Table foo 
=========== 
id | val 
-------- 
01 | 'a' 
02 | 'b' 
03 | 'c' 
04 | 'a' 
05 | 'b' 

Table bar 
============ 
id | class 
------------- 
01 | 'classH' 
02 | 'classI' 
03 | 'classJ' 
04 | 'classK' 
05 | 'classI' 

我想返回FOO的所有值和酒吧，是其中富在多個不同的酒吧存在。因此，在此示例中，我們將返回：

val | class 
------------- 
'a' | 'classH' 
'a' | 'classK' 

因爲儘管'b'也存在多次，它也具有相同的bar值。

我有以下查詢返回的其中有多個酒吧都富，就算了吧是相同的：

select distinct foo.val, bar.class 
from foo, bar 
where foo.id = bar.id 
and 
(
    select count(*) from 
    foo2, bar2 
    where foo2.id = bar2.id 
    and foo2.val = foo.val 
) > 1 
order by 
va.name; 

Answer 1

select f.val, b.class 
from foo f 
join bar b on f.id = b.id 
where f.val in (
    select f.val 
    from foo f 
    join bar b on f.id = b.id 
    group by f.val 
    having count(distinct b.class) > 1 
); 

Answer 2

你可以使用具有全部重複，以顯示每個子查詢使用EXISTS行像這樣。

SELECT f.val, b.class 
FROM foo f 
JOIN bar b ON b.id = f.id 
WHERE EXISTS 
( SELECT 1 
    FROM foo 
    JOIN bar ON foo.id = bar.id 
    WHERE foo.val = f.val 
    GROUP BY foo.val 
    HAVING COUNT(DISTINCT bar.class) > 1 
); 

Fiddle Demo

普遍存在執行比這就是爲什麼我喜歡它了...更多細節關於VS存在MY POST HERE

Answer 3

你可以做一個子查詢，以獲得更快的人口從符合條件（名稱）的foo開始。然後加入回兩個表，以獲得您想要的信息輸出：

select f.val, b.class 
from (select f.val 
     from foo f join 
      bar b 
      on f.id = b.id 
     group by f.val 
     having count(distinct b.class) > 1 
    ) bf join 
    foo f 
    on bf.val = f.val join 
    bar b 
    on f.id = b.id 

Answer 4

select f.val, b.class 
    from foo f 
    join bar b 
    on f.id = b.id 
    join (select f.val 
      from foo f 
      join bar b 
      on f.id = b.id 
     group by f.val 
     having count(distinct b.class) > 1) v 
    on b.val = v.val