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C++ newbie here。valgrind和openmp,仍然可到達並可能丟失,是不是很糟糕?
過去幾天我一直在提高自己的記憶管理技能,而且根據valgrind,我的程序不再泄漏內存。事實上,我根本沒有收到valgrind的警告。
然而,當我加入的OpenMP循環放入我的代碼,我開始變得在Valgrind的下列錯誤(MEMCHECK):(但沒有絕對丟失塊)
==6417== 304 bytes in 1 blocks are possibly lost in loss record 3 of 4
==6417== at 0x4C279FC: calloc (vg_replace_malloc.c:467)
==6417== by 0x4011868: _dl_allocate_tls (dl-tls.c:300)
==6417== by 0x6649871: [email protected]@GLIBC_2.2.5 (allocatestack.c:570)
==6417== by 0x62263DF: ??? (in /usr/lib/x86_64-linux-gnu/libgomp.so.1.0.0)
==6417== by 0x42A2BB: Blade::updatePanels() (blade.cpp:187)
==6417== by 0x418677: VLMsolver::initialiseBlade() (vlmsolver.cpp:590)
==6417== by 0x415A1B: VLMsolver::start(std::string) (vlmsolver.cpp:80)
==6417== by 0x40B28C: main (charybdis.cpp:176)
和:
==6417== 1,568 bytes in 1 blocks are still reachable in loss record 4 of 4
==6417== at 0x4C28FAC: malloc (vg_replace_malloc.c:236)
==6417== by 0x6221578: ??? (in /usr/lib/x86_64-linux-gnu/libgomp.so.1.0.0)
==6417== by 0x6226044: ??? (in /usr/lib/x86_64-linux-gnu/libgomp.so.1.0.0)
==6417== by 0x622509B: GOMP_parallel_start (in /usr/lib/x86_64-linux-gnu/libgomp.so.1.0.0)
==6417== by 0x41AF58: VLMsolver::segmentCirculations() (vlmsolver.cpp:943)
==6417== by 0x415E4B: VLMsolver::solveManager() (vlmsolver.cpp:177)
==6417== by 0x415A4B: VLMsolver::start(std::string) (vlmsolver.cpp:91)
==6417== by 0x40B28C: main (charybdis.cpp:176)
這是valgrind不理解openmp的情況嗎?或者它可能會變成陰險的東西?
請注意,當我使用helgrind運行valgrind時,在讀取期間(和寫入)消息會得到數千次「可能的數據競爭」。然而,我的程序(流體動力學求解器)對openmp和serial代碼都給出了相同的結果。如果您對此問題感興趣,我可以提供helgrind錯誤和相關部分。
否則現在,下面是第二條消息的違規代碼:943行是編譯指示行。
for (int b = 0;b < sNumberOfBlades;++b) {
*VLMSOLVER.CPP LINE 943 is next*:
#pragma omp parallel for collapse(2) num_threads(2) firstprivate(b)
for (int i = 0;i<numX;++i) {
for (int j = 0;j<numY;++j) {
if (j == 0) {
blades[b].line[i*numNodesY+j].circulation = blades[b].panel[i*numY+j].circulation;
} else {
blades[b].line[i*numNodesY+j].circulation = blades[b].panel[i*numY+j].circulation - blades[b].panel[i*numY+j-1].circulation;
}
if (j==numY-1) {
blades[b].line[i*numNodesY+j+1].circulation = -1 * blades[b].panel[i*numY+j].circulation;
}
}
}
if (sBladeSymmetry) {
break;
}
}
int k = numX*numNodesY;
for (int b = 0;b < sNumberOfBlades;++b) {
for (int i = 0;i<numX;++i) {
for (int j = 0;j<numY;++j) {
if (i == 0) {
blades[b].line[k+i*numY+j].circulation = - 1 * blades[b].panel[i*numY+j].circulation;
} else {
blades[b].line[k+i*numY+j].circulation = -1 * blades[b].panel[i*numY+j].circulation + blades[b].panel[(i-1)*numY+j].circulation;
}
if (i==numX-1) {
blades[b].line[k+(i+1)*numY+j].circulation = blades[b].panel[i*numY+j].circulation;
}
}
}
if (sBladeSymmetry) {
break;
}
}
因此,讓內存仍然可以訪問是openmp的一個特性,就像它在STL情況下的情況一樣,就像在那個鏈接中一樣? – CptLightning
@CptLightning:我會這麼認爲的,但是我沒有真正與OpenMP合作過,所以我不能肯定地說這是事實。您需要查看OpenMP是否也使用與STL相同的基礎知識,鏈接將解釋和討論。 –