3
SELECT COUNT(pkNotification) AS caseTotal
,COUNT(fkCaseType) AS Suspected
, COUNT(fkCaseType) AS Confirmed
, Disease.Name
FROM [Notification]
INNER JOIN [Disease] ON Notification.fkDisease=Disease.pkDisease
GROUP BY Disease.Name
這是我的說法。但是我需要COUNT(fkCaseType)AS Suspected只有當fkCaseType = 1並且確認爲fkcaseType = 2時。對於SELECT語句中具有GROUP BY的COUNT的SQL WHERE
問題是我在哪裏做子查詢,我遇到了問題。