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我有一個季度頻率和3個時間變量的數據幀,其中時間是一個字符變量。數據幀如下所示使用季度頻率從字符中轉換時間變量
dt <- structure(list(
name1 = c("C","C","C","C","C","C","B","B","B","B","B","B"),
name2 = c("D","E","A","D","E","A","D","E","A","D","E","A"),
year = c(2012, 2012, 2012, 2010, 2010, 2010, 2012, 2012, 2012, 2010, 2010, 2010),
quarter = c(4,4,4,1,1,1,4,4,4,1,1,1),
time = c("2012q4", "2012q4","2012q4","2010q1", "2010q1","2010q1","2012q4", "2012q4","2012q4","2010q1", "2010q1","2010q1")),
.Names = c("name1","name2","year", "quarter", "time"),
row.names = c("1", "2", "3", "4", "5", "6", "7", "8", "9", "10", "11", "12"), class =("data.frame"))
我想時間設置爲我的時間序列變量,排序名1(按字母順序),NAME2(按字母順序)和時間(按時間順序)的數據幀。期望的輸出應該是
dt <- structure(list(
name1 = c("B","B","B","B","B","B", "C","C","C","C","C","C"),
name2 = c("A", "A", "D", "D", "E", "E","A", "A", "D", "D", "E", "E"),
year = c(2010,2012,2010,2012,2010,2012,2010,2012,2010,2012,2010,2012),
quarter = c(1,4,1,4,1,4,1,4,1,4,1,4),
time = c("2010q1","2012q4", "2010q1","2012q4","2010q1","2012q4","2010q1","2012q4","2010q1","2012q4","2010q1","2012q4")),
.Names = c("name1","name2","year", "quarter", "time"),
row.names = c("1", "2", "3", "4", "5", "6", "7", "8", "9", "10", "11", "12"), class =("data.frame"))
我試過了。
dt$time <- as.yearqtr(dt$time)
dt <- dt[order(dt$name1, dt$name2, dt$time),]
在此先感謝。
你嘗試過的東西是不是工作?我看到的唯一可能的區別是你的宿舍現在處於'yearqtr'對象而不是字符串。如果你做'dt $ time = format(dt $ time,「%Y Q%q」)'讓他們回到「2012 Q2」格式,那麼你會怎樣? – Spacedman