熊貓插入「：」入數值

我有DF：熊貓插入「：」入數值

CU     Parameters   01-04-2017 02-04-2017 
CU0111--H Time of Full Charge  732   726 
CU0111-016297-2 Time of Full Charge  825   815 
CU0111-020046-K Time of Full Charge  849   836 
CU0111-023156-H Time of Full Charge  922   907 
CU0111-023349-J Time of Full Charge  1121   1010 
CU0111-023350-L Time of Full Charge  1021   932

與日期列中的值實際上是時間的日值。如何將它們轉換爲H：MM值，使DF1：

CU    Parameters    01-04-2017 02-04-2017 
CU0111--H Time of Full Charge  7:32  7:26 
CU0111-016297-2 Time of Full Charge  8:25  8:15 
CU0111-020046-K Time of Full Charge  8:49  8:36 
CU0111-023156-H Time of Full Charge  9:22  9:07 
CU0111-023349-J Time of Full Charge  11:21  10:10 
CU0111-023350-L Time of Full Charge  10:21  9:32

來源

2017-05-07 wazzahenry

如果你想要的「H：MM」：如果你想使用一個適當的

text = df['01-04-2017'].astype(str) 
df['01-04-2017'] = text.str[:-2] + ':' + text.str[-2:]

字符串值，這樣做時間D型：

hhmm = df['01-04-2017'] 
minutes = (hhmm/100).astype(int) * 60 + hhmm % 100 
df['01-04-2017'] = pd.to_timedelta(minutes, 'm')

然後你得到這樣的：

0 07:32:00 
1 08:25:00 
... 
dtype: timedelta64[ns]

我通常更喜歡後一種方法，尤其是如果您打算在晚些時候使用這些數據。第一種基於字符串的方法只有在工作流程中的下一步需要字符串時才非常合適。

來源

2017-05-07 10:34:30

一個襯爲所有列：

In [44]: (df.set_index(['CU','Parameters']) 
    ...: .stack() 
    ...: .astype(str) 
    ...: .str.zfill(4) 
    ...: .str.replace(r'(\d{2})(\d{2})', r'\1:\2') 
    ...: .unstack() 
    ...: .reset_index() 
    ...:) 
    ...: 
Out[44]: 
       CU   Parameters 01-04-2017 02-04-2017 
0 CU0111--H Time of Full Charge  07:32  07:26 
1 CU0111-016297-2 Time of Full Charge  08:25  08:15 
2 CU0111-020046-K Time of Full Charge  08:49  08:36 
3 CU0111-023156-H Time of Full Charge  09:22  09:07 
4 CU0111-023349-J Time of Full Charge  11:21  10:10 
5 CU0111-023350-L Time of Full Charge  10:21  09:32

來源

2017-05-07 11:04:17 MaxU

熊貓插入「：」入數值

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