TSQL在存儲過程中解析XML

表1包含問題表2包含組表3包含選項表4包含有用於配置文件數據

簡檔數據被生成並轉換爲XML，並存儲在profileData列上的列工作申請表4.它的格式是這樣：

<proficiencies> 
<question> 
    <questionID>2</questionID> 
    <questionGroup>2</questionGroup> 
    <questionOptions> 
    <option>19</option> 
    <option>20</option> 
    <option>31</option> 
    </questionOptions> 
</question> 
<question> 
    <questionID>1</questionID> 
    <questionGroup>1</questionGroup> 
    <questionOptions> 
    <option>20</option> 
    <option>29</option> 
    <option>21</option> 
    </questionOptions> 
</question> 
<question> 
    <questionID>3</questionID> 
    <questionGroup>2</questionGroup> 
    <questionOptions> 
    <option>18</option> 
    <option>29</option> 
    </questionOptions> 
</question> 
</proficiencies>

現在，我創建了一個網頁，我需要重新創建與所有這些選擇的設置工作申請。當我創建XML時，我使用的是與實際問題和信息相關的ID號碼。

什麼是能夠找出這些身份證號碼現在的最佳方式？我想在存儲過程中最好這樣做，因爲如果我在javascript中解析它時，它會有很多數據庫調用。

只是不知道如何最好地去解決這個問題或改變我的數據庫結構。

在這個例子中，我需要找出問題是什麼地方的問題ID = 2等

有沒有更好的方式來做到這一點？

來源

2013-12-19 SBB

，你能否告訴我們您使用格式化爲XML之前提取數據的查詢？ – Rikalous

數據在列中以XML格式存儲，我基於它們選擇的所有選項ID在JavaScript中創建它。然後我將它作爲一個xml塊存儲。現在我需要通過該XML塊，並找出這些ID是 – SBB

用於顯示目的我將使用數據表/數據集。很少幾行，你就完成了。 – KumarHarsh

我認爲你正在尋找XQuery。

以下示例解析出您的XML並將其連接到問題表。它使用nodes(),query()和value()方法。

with MyXML 
as 
(
select 
1 as MyXMLDataID 
,cast(' 
<proficiencies> 
<question> 
    <questionID>2</questionID> 
    <questionGroup>2</questionGroup> 
    <questionOptions> 
    <option>19</option> 
    <option>20</option> 
    <option>31</option> 
    </questionOptions> 
</question> 
<question> 
    <questionID>1</questionID> 
    <questionGroup>1</questionGroup> 
    <questionOptions> 
    <option>20</option> 
    <option>29</option> 
    <option>21</option> 
    </questionOptions> 
</question> 
<question> 
    <questionID>3</questionID> 
    <questionGroup>2</questionGroup> 
    <questionOptions> 
    <option>18</option> 
    <option>29</option> 
    </questionOptions> 
</question> 
</proficiencies>' as xml) as MyXMLData), 
MyQuestionGroups 
as 
(
select 1 as questionGroup, 'Education' as questionGroup_description 
union 
select 2 as questionGroup, 'Experience' as questionGroup_description 
), 
MyQuestions 
as 
(
select 1 as questionGroup, 1 as questionID, 'High school attendance' as question 
union 
select 2 as questionGroup, 2 as questionID, 'Alchemy experience' as question 
union 
select 2 as questionGroup, 3 as questionID, 'Arbitrage experience' as question 
), 
MyOptions 
as 
(
select 18 as optionID, '1 year' as option_description 
union 
select 19 as optionID, '2 year' as option_description 
union 
select 20 as optionID, '3 years' as option_description 
union 
select 21 as optionID, '4 year' as option_description 
union 
select 29 as optionID, '5 year' as option_description 
union 
select 31 as optionID, '6 years' as option_description 
) 
SELECT MyXML.MyXMLDataID 
     ,t1.questionID.query('.') as questionID_node 
     ,q.question 
    FROM MyXML 
CROSS APPLY MyXMLData.nodes('/proficiencies/question/questionID') as t1(questionID) 
INNER JOIN MyQuestions q 
     on q.questionID = t1.questionID.value('.', 'int')

它返回這樣的結果：

----------------------------------------------- 
MyXMLDataID questionID_node question 
----------------------------------------------- 
1 <questionID>2</questionID> Alchemy experience 
1 <questionID>1</questionID> High school attendance 
1 <questionID>3</questionID> Arbitrage experience

來源

2013-12-22 16:35:48

TSQL在存儲過程中解析XML

回答

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