select count（*）and count（*）where column is not null in single query

Question

我有兩張表employee和stores員工會有一定的店鋪分配他的職責是填寫店裏的店鋪地址table我有40k店鋪分貝

我想得到所有商店的數量和地址填補商店的數量。

$sql = "select count(*) from stores"; 

上面的查詢將返回所有STORS的數量如何獲得地址填寫門店數量在同一查詢，而不是

$sql = "select count(*) from stores where address is not null" 

Answer 1

你似乎是新的SQL。您可以輕鬆地使用計算一個COUNT()列的非NULL值：學習SQL

select count(*), count(address) 
from stores; 

最良好的祝願。

Answer 2

使用sum()代替count()

試一下：

select count(*) as count_all , SUM(if(address is not null, 1, 0)) AS count2 
from stores