乘記錄我的成熟

Question

輸入：

我有4個表中的列：

KONTO CUSTOMER_NUMBER COLLATERAL_TYPE MATURITY 

Konto的獨特價值，到期日價值，我需要繁殖。

例子：

KONTO CUSTOMER_NUMBER COLLATERAL_TYPE MATURITY 
-------------------------------------------------- 
1   000234   H    4 
2   000234   G    3 
3   212567   H    5 

我需要創建表，每KONTO乘以我的最大的成熟度和每個客戶的抵押品類型。也許它更容易說，每個抵押品應該有記錄FER每年到期

輸出：

KONTO CUSTOMER_NUMBER COLLATERAL_TYPE MATURITY 
------------------------------------------------- 
1   000234   H    1 
1   000234   H    2 
1   000234   H    3 
1   000234   H    4 
2   000234   G    1 
2   000234   G    2 
2   000234   G    3 
3   212567   H    1 
3   212567   H    2 
3   212567   H    3 
3   212567   H    4 
3   212567   H    5 

我從其他公司的同事們成功地做到這一點，但我不知道怎麼辦。

我在MS Access中使用MS Access/SQL。

謝謝你，我的英文不好

Answer 1

抱歉，這是在MS Access，它不具有熱膨脹係數和窗函數真的很痛苦。一種方法是：

select KONTO, CUSTOMER_NUMBER, COLLATERAL_TYPE, 1 as MATURITY 
from t 
where MATURITY >= 1 
union all 
select KONTO, CUSTOMER_NUMBER, COLLATERAL_TYPE, 2 as MATURITY 
from t 
where MATURITY >= 2 
union all 
select KONTO, CUSTOMER_NUMBER, COLLATERAL_TYPE, 3 as MATURITY 
from t 
where MATURITY >= 3 
union all 
select KONTO, CUSTOMER_NUMBER, COLLATERAL_TYPE, 4 as MATURITY 
from t 
where MATURITY >= 4 
union all 
select KONTO, CUSTOMER_NUMBER, COLLATERAL_TYPE, 5 as MATURITY 
from t 
where MATURITY >= 5; 

當然，您將不得不重複這種模式，直到您的最大成熟度。

Answer 2

您可以使用笛卡爾（乘）查詢：

SELECT DISTINCT 
    KontoTable.Konto, 
    KontoTable.Customer_Number, 
    KontoTable.Collateral_Type, 
    10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10) AS Maturity 
FROM 
    MSysObjects AS Uno, 
    MSysObjects AS Deca, 
    KontoTable 
WHERE 
    ((10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10)) 
    Between 1 And KontoTable.Maturity);