是否可以使用閉包從值列表中創建一組變量? 詢問這樣做的原因是基於(比如說)兩個三四個或五個部分 當然這裏的代碼不能正常工作清單上創建一些遞歸功能,但任何指針將helpful.then常規閉包實例化變量
def longthing = 'A for B with C in D on E'
//eg shopping for 30 mins with Fiona in Birmingham on Friday at 15:00
def breaks = [" on ", " in ", "with ", " for "]
def vary = ['when', 'place', 'with', 'event']
i = 0
line = place = with = event = ""
breaks.each{
shortline = longthing.split(breaks[i])
longthing= shortline[0]
//this is the line which obviously will not work
${vary[i]} = shortline[1]
rez[i] = shortline[1]
i++
}
return place + "; " + with + "; " + event
// looking for answer of D; C; B
編輯>>
是的,我試圖找到收拾這個,這是我在每個循環後做了更巧妙的方式
len = rez[3].trim()
if(len.contains("all")){
len = "all"
} else if (len.contains(" ")){
len = len.substring(0, len.indexOf(" ")+2)
}
len = len.replaceAll(" ", "")
with = rez[2].trim()
place = rez[1].trim()
when = rez[0].trim()
event = shortline[0]
,如果我決定到另一個項目添加到列表(我只是這樣做)我必須記住其中[I]它是成功地提取它
這是再解析日期/次,然後用jChronic自然文本轉換成公曆信息,所以我就可以在谷歌日曆設置一個事件,工人的部分
我重讀了你的問題,我不明白你在做什麼。我認爲我的答案會對你有所幫助,但如果你能舉一個你的手術結果的例子,我會更有幫助。 – hvgotcodes 2010-12-06 15:39:58