用lodash簡化表達式

Question

我想用lodash簡化這個函數，但是我不知道該怎麼做才能幫助我？

function _findMembers(usersAvailable,listOfUsers){ 
    console.log("listOfUsers") 
    console.log(listOfUsers) 
    var members = []; 
    for(var i=0; i<_.size(usersAvailable);i++){ 
     for(var j=0; j<_.size(listOfUsers); j++){ 
      if(usersAvailable[i].local.email == listOfUsers[j]){ 
       var user = usersAvailable[i]; 
       user.selected = true; 
       members.push(user); 
      } 
     } 
    } 
    console.log("members") 
    console.log(members) 
    return members; 
} 

Answer 1

使用loash

• https://lodash.com/docs#filter

的lodash濾波函數，並且包括JavaScript函數

• https://developer.mozilla.org/fr/docs/Web/JavaScript/Reference/Objets_globaux/Array/includes

你可以嘗試這樣的事：

var members = usersAvailable.filter(function (currentUser) { 
     if(listOfUsers.includes(currentUser.local.email)){ 
      currentUser.selected=true; 
      return true; 
     }else{ 
      return false 
     } 
     return listOfUsers.includes(currentUser.local.email); 
    }); 

Answer 2

你並不需要使用lodash。只需使用標準的JavaScript過濾功能：

function _findMembers(usersAvailable, listOfUsers){  
    return usersAvailable.filter(function(userAvailable) { 
     return listOfUsers.indexOf(userAvailable.local.email) > -1; 
    }); 
}