對於每個獨特的GroupId
我希望得到每個IsGreen
,IsRound
,IsLoud
條件和總行數的計數。計算組內的每個條件
的樣本數據:
-----------------------------------------------------
id | ItemId | GroupId | IsGreen | IsRound | IsLoud
----+--------+---------+---------+---------+---------
1 | 1001 | 1 | 0 | 1 | 1
2 | 1002 | 1 | 1 | 1 | 0
3 | 1003 | 2 | 0 | 0 | 0
4 | 1004 | 2 | 1 | 0 | 1
5 | 1005 | 2 | 0 | 0 | 0
6 | 1006 | 3 | 0 | 0 | 0
7 | 1007 | 3 | 0 | 0 | 0
期望的結果:
----------------------------------------------------------
GroupId | TotalRows | TotalGreen | TotalRound | TotalLoud
--------+-----------+------------+------------+-----------
1 | 2 | 1 | 2 | 1
2 | 3 | 1 | 0 | 1
3 | 2 | 0 | 0 | 0
我用下面的代碼來創建表,我遇到的問題是,如果任何的組中沒有行匹配組未出現在最終表中的條件之一。完成我想要做的事的最佳方式是什麼?
SELECT total.GroupId
, total.[Count] AS TotalRows
, IsGreen.[Count] AS TotalGreen
, IsRound.[Count] AS TotalRound
, IsLoud.[Count] AS TotalLoud
FROM (
SELECT GroupId
, count(*) AS [Count]
FROM TestData
GROUP BY GroupId
) TotalRows
INNER JOIN (
SELECT GroupId
, count(*) AS [Count]
FROM TestData
WHERE IsGreen = 1
GROUP BY GroupId
) IsGreen ON IsGreen.GroupId = TotalRows.GroupId
INNER JOIN (
SELECT GroupId
, count(*) AS [Count]
FROM TestData
WHERE IsRound = 1
GROUP BY GroupId
) IsRound ON IsRound.GroupId = TotalRows.GroupId
INNER JOIN (
SELECT GroupId
, count(*) AS [Count]
FROM TestData
WHERE IsLoud = 1
GROUP BY GroupId
) IsLoud ON IsLoud.GroupId = TotalRows.GroupId
爲什麼不是這個由groupID'簡單'組和'count'和'總和?' – xQbert
如果你改變了所有的內部連接到左外連接您的代碼將正常工作。 – Matt