不同於複雜的sql查詢

Question

我還有一個給你們。我已經搜索過，但我無法弄清楚這個問題的原因。

基本上，我想對user_id做一個DISTINCT，它是一個自然加入並存在於表「user」和「leaderboard_entry」中的列。

這是我的原始查詢，它的效果很好，但我想過濾出重複項，並只顯示第一個最快的用戶分數。內部查詢基本上抓取了最近的100行，而外部查詢通過升序leaderboard_entry_elapsed_time_ms來衡量它們。 「leaderboard_entry *，」

set @t1=0; select * from 
( 
    select @t1 := @t1+1 as leaderboard_entry_youngness_rank, 1-@t1/100 as 
    leaderboard_entry_youngness_based_on_expiry, 
    leaderboard_entry.*, 
    NOW()-leaderboard_entry_timestamp as leaderboard_entry_age_in_some_units , 
    TO_DAYS(NOW())-TO_DAYS(leaderboard_entry_timestamp) 
    as leaderboard_entry_age_in_days , leaderboard.leaderboard_quiz_mode , 
    leaderboard.leaderboard_load_key , 
    user.user_name 
    from leaderboard_entry 
    natural join 
    leaderboard 
    natural join 
    user 
    where 
    (leaderboard_load_key = 'es-en-animals-1' 
    or leaderboard_load_key = '-es-en-animals-1') 
    and leaderboard_quiz_mode = '0' 
    order by leaderboard_entry_age_in_some_units asc , 
    leaderboard_entry_timestamp asc limit 0, 100 
) as outer_temp 
order by 
    leaderboard_entry_elapsed_time_ms asc , 
    leaderboard_entry_timestamp asc 
limit 0, 50 

我試過以下，這是去除與列的明確命名添加DISTINCT關鍵字一樣，所以我需要：

set @t1=0; select * from 
( 
    select @t1 := @t1+1 as leaderboard_entry_youngness_rank, 1-@t1/100 as 
    leaderboard_entry_youngness_based_on_expiry,
 

NOW()-leaderboard_entry_timestamp as leaderboard_entry_age_in_some_units , TO_DAYS(NOW())-TO_DAYS(leaderboard_entry_timestamp) as leaderboard_entry_age_in_days , leaderboard.leaderboard_quiz_mode , leaderboard.leaderboard_load_key , user.user_name
 

distinct leaderboard_entry.user_id, leaderboard_entry.leaderboard_entry_id, leaderboard_entry.leaderboard_id, leaderboard_entry.leaderboard_entry_timestamp, leaderboard_entry.leaderboard_entry_elapsed_time_ms,
 

from leaderboard_entry natural join leaderboard natural join user where (leaderboard_load_key = 'es-en-animals-1' or leaderboard_load_key = '-es-en-animals-1') and leaderboard_quiz_mode = '0' order by leaderboard_entry_age_in_some_units asc , leaderboard_entry_timestamp asc limit 0, 100 ) as outer_temp order by leaderboard_entry_elapsed_time_ms asc , leaderboard_entry_timestamp asc limit 0, 50 

，但我得到這個錯誤，它沒有任何意義... :(

#1064 - You have an error in your SQL syntax; 
check the manual that corresponds to your MySQL 
server version for the right syntax to use near 
'distinct leaderboard_entry.user_id, leaderboard_entry.leaderboard_entry_id, ' 
at line 12 

任何幫助，非常感謝！ 豬

Answer 1

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