5
運行此按預期工作:如何創建一個懶惰-seq的矢量
(defn long-seq [n]
(lazy-seq (cons
(list n {:somekey (* n 2)})
(long-seq (+ n 1)))))
(take 3 (long-seq 3))
; => ((3 {:somekey 6}) (4 {:somekey 8}) (5 {:somekey 10}))
但是我希望做一個向量同樣的事情:
(defn long-seq-vec [n]
(lazy-seq (into
(vector (list n {:somekey (* n 2)}))
(long-seq-vec (+ n 1)))))
(take 3 (long-seq-vec 3))
這給了我一疊溢出。爲什麼?