嗨,大家好我即將創建遊戲和即時通訊新的sql lite。我有一個代碼插入數據庫,但我不知道如何最大限度地在10,也不知道如何比較新分數的球員和舊分數。如果新的得分擊敗前10名得分中的1名,我該如何刪除前10名中最低的得分。即時尋找偉大的代碼和良好的解釋,以便我會理解代碼的流程。數據庫最多10個,並根據分數排序,並刪除替換分數,如果它是最低
我的繼承人數據庫類:
public class highscore {
private static final String DATABASE_NAME = "topscoredb";
private static final String DATABASE_TABLE = "tablescore";
private static final int DATABASE_VERSION = 2;
public static final String KEY_ROWID = "_id";
public static final String KEY_SCORE = "score";
public static final String KEY_NAME = "players_name";
private DbHelper ourHelper;
private final Context ourContext;
private SQLiteDatabase ourDatabase;
private static class DbHelper extends SQLiteOpenHelper{
public DbHelper(Context context) {
super(context, DATABASE_NAME, null, DATABASE_VERSION);
// TODO Auto-generated constructor stub
}
@Override
public void onCreate(SQLiteDatabase db) {
// TODO Auto-generated method stub
db.execSQL("CREATE TABLE " + DATABASE_TABLE + " (" +
KEY_ROWID + " INTEGER PRIMARY KEY AUTOINCREMENT, " +
KEY_NAME + " TEXT NOT NULL, " +
KEY_SCORE + " TEXT NOT NULL);"
);
}
@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion,
int newVersion) {
// TODO Auto-generated method stub
db.execSQL("DROP TABLE IF EXIST" + DATABASE_TABLE);
onCreate(db);
}
}
public highscore(Context c){
ourContext = c;
}
public highscore open() throws SQLException{
ourHelper = new DbHelper(ourContext);
ourDatabase = ourHelper.getWritableDatabase();
return this;
}
public void close(){
ourHelper.close();
}
public long createEntry(String name, String tscore) {
// TODO Auto-generated method stub
ContentValues cv = new ContentValues();
cv.put(KEY_NAME, name);
cv.put(KEY_SCORE, tscore);
return ourDatabase.insert(DATABASE_TABLE, null, cv);
}
public String getData() {
String[] columns = new String[]{ KEY_ROWID, KEY_NAME, KEY_SCORE};
Cursor c = ourDatabase.query(DATABASE_TABLE, columns, null, null, null,null, null);
String result = "";
int irow = c.getColumnIndex(KEY_ROWID);
int iname = c.getColumnIndex(KEY_NAME);
int iscore = c.getColumnIndex(KEY_SCORE);
for(c.moveToFirst(); !c.isAfterLast(); c.moveToNext()){
result = result + c.getString(irow)+ " " +c.getString(iname)+" "+
c.getString(iscore) + "\n";
}
return result;
}
}
我應該使用方法?
類似的答案已經在stackoverflow.http://stackoverflow.com/questions/2035670/limit-an-sqlite-tables-maximum-number-行之間?rq = 1 –
在某種程度上相似,但它是不同的編碼在android –