SQL舍入機制

Question

我對舍入有以下問題。

SQL Server 2005中

SELECT ROUND(82.05,1) AS [Round Amount] 

Result 
[82.10] 

SELECT ROUND(82.07,1) AS [Round Amount] 
Result 
[82.10] 

如何自定義舍入函數作爲下面的圖？

Answer 1

SELECT ROUND(82.01*2,1)/2 AS [Round Amount] 
82.00 
SELECT ROUND(82.02*2,1)/2 AS [Round Amount] 
82.00 
SELECT ROUND(82.03*2,1)/2 AS [Round Amount] 
82.05 
SELECT ROUND(82.04*2,1)/2 AS [Round Amount] 
82.05 
SELECT ROUND(82.05*2,1)/2 AS [Round Amount] 
82.05 
SELECT ROUND(82.06*2,1)/2 AS [Round Amount] 
82.05 
SELECT ROUND(82.07*2,1)/2 AS [Round Amount] 
82.05 
SELECT ROUND(82.08*2,1)/2 AS [Round Amount] 
82.10 
SELECT ROUND(82.09*2,1)/2 AS [Round Amount] 
82.10