如何扁平化JSON從一個陣列到大熊貓

Question

我有一個JSON：

[{ 
"analogData": [ 
[122483,104],[122493,100],[122503,106],[122513,106],[122523,107] 
[122533,99],[122543,103],[122553,98],[122563,106],[122573,95], 
[122583,98],[122593,97],[122603,95],[122613,101],[122623,99], 
[122633,98],[122643,101],[122653,102],[122663,105],[122673,99], 
[122683,102],[122693,107],[122703,106],[122713,108],[122723, 99], 
[122733,98],[122743,104],[122753,104],[122763,96],[122773,99]] 
"upTime": 132833,"deviceId": "5c6d27a","state": "idle"}, next 30 readings, ...]" 

它再次爲下一組重複。

我已經能夠在JSON加載到數據幀和它出來爲：

... 0 [[122483, 104], [122493, 100], [122503, 106], ... 
1  [[41614, 103], [41624, 105], [41634, 102], [41... 
2  [[22674, 113], [22684, 89], [22694, 106], [227... 
3  [[220570, 81], [220580, 81], [220590, 81], [22... 
4  [[160474, 85], [160484, 86], [160494, 86], [16... 

我想獲得「analogData」格式化成一個數據幀有4列：指數，正常運行時間，時間，

水平

index uptime time level 
1  132833 122483 104 
2  132833 122493 100 
3  132833 122503 106 

...

Answer 1

基本上，您使用Json API將JSON加載到字典中，然後根據需要提取這些值。

做一個Python的方式：

my_json = '{"analogData": [[122483,104],[122493,100],[122503,106],[122513,106],[122523,107],[122533,99],[122543,103],[122553,98],[122563,106],[122573,95],[122583,98],[122593,97],[122603,95],[122613,101],[122623,99],[122633,98],[122643,101],[122653,102],[122663,105],[122673,99],[122683,102],[122693,107],[122703,106],[122713,108],[122723, 99],[122733,98],[122743,104],[122753,104],[122763,96],[122773,99]], "upTime": 132833,"deviceId": "5c6d27a","state": "idle"}' 

buffer = json.loads(my_json) 
aD = buffer["analogData"] 
uT = buffer["upTime"] 
print([[i+1, uT] + aD[i] for i in range(len(aD))]) 

輸出：

[[1, 132833, 122483, 104], [2, 132833, 122493, 100], [3, 132833, 122503, 106], [4, 132833, 122513, 106], [5, 132833, 122523, 107], [6, 132833, 122533, 99], [7, 132833, 122543, 103], [8, 132833, 122553, 98], [9, 132833, 122563, 106], [10, 132833, 122573, 95], [11, 132833, 122583, 98], [12, 132833, 122593, 97], [13, 132833, 122603, 95], [14, 132833, 122613, 101], [15, 132833, 122623, 99], [16, 132833, 122633, 98], [17, 132833, 122643, 101], [18, 132833, 122653, 102], [19, 132833, 122663, 105], [20, 132833, 122673, 99], [21, 132833, 122683, 102], [22, 132833, 122693, 107], [23, 132833, 122703, 106], [24, 132833, 122713, 108], [25, 132833, 122723, 99], [26, 132833, 122733, 98], [27, 132833, 122743, 104], [28, 132833, 122753, 104], [29, 132833, 122763, 96], [30, 132833, 122773, 99]] 

Answer 2

假設JSON數據加載到一個變量data，也許你可以嘗試一些數據結構操作？

data = {} 

# load up the JSON file, assuming that's how it's saved 
with open("test.json") as json_file: 
    data = json.load(json_file) # now a Python list of dict 

new_data = [] 
temp_data = {} # for temporary use 

for col in data: # iterate through the data 
    for row in col["analogData"]: 
     temp_data["uptime"] = col["upTime"] 
     # split up the analogData tuple-like lists 
     temp_data["analogData"], temp_data["level"] = row 
     new_data.append(temp_data) 

     temp_data = {} # reset row 

df = pandas.DataFrame(new_data) 

不能確定你希望你index列，但創建一個數據幀時，熊貓使得其默認索引列。