foreach循環中的更新表

有問題。只是找不到問題。我有兩張牌第一張牌：hold1，hold2，hold1goal，hold2goal和另一個hold：hold，fgoal，agol。我試圖讓所有hold1goal和hold2goal在保持表中的fgoal和agoal。我相當新的SQL。foreach循環中的更新表

<?php 
include "config.php"; 

foreach($db->query('SELECT * FROM kampe') as $row){ 

     $fgoal = $row['hold1goal']; 
     $agoal = $row['hold2goal']; 
     $hold = $row['hold1']; 

     $stmt = $db->prepare("UPDATE hold SET fgoal = :fgoal, agoal = :agoal WHERE hold = :hold");         
     $stmt->bindParam(':fgoal', $fgoal); 
     $stmt->bindParam(':agoal', $agoal); 
     $stmt->bindParam(':hold', $hold); 


     $stmt->execute(); 


     /* print $agoal . "\n"; 

     $fgoal = $row['hold2goal']; 
     $agoal = $row['hold1goal']; 
     $hold = $row['hold2']; 

     $stmt = $db->prepare("UPDATE hold SET fgoal = :fgoal, agoal = :agoal WHERE hold = :hold");         
     $stmt->bindParam(':fgoal', $fgoal); 
     $stmt->bindParam(':agoal', $agoal); 
     $stmt->bindParam(':hold', $hold); 



     $stmt->execute(); */ 
} 
?>

這是結果。只有'Odensevej'發生了變化。認爲foreach循環會改變所有。

申佩

INSERT INTO `kampe` (`kampID`, `hold1`, `hold2`, `hold1goal`, `hold2goal`) VALUES 
(1, 'marksvej', 'holdet', 0, 0), 
(2, 'tervej', 'dfdf', 0, 0), 
(3, 'Odensevej', 'holdet2', 2, 1), 
(4, 'hest', 'hestener', 0, 0), 
(5, 'holdet', 'tervej', 0, 0), 
(6, 'dfdf', 'marksvej', 2, 6), 
(7, 'Odensevej', 'hest', 0, 0), 
(8, 'hestener', 'holdet2', 3, 1), 
(9, 'dfdf', 'holdet', 0, 0), 
(10, 'tervej', 'marksvej', 0, 0), 
(11, 'hestener', 'Odensevej', 2, 1), 
(12, 'holdet2', 'hest', 0, 0), 
(13, 'Odensevej', 'holdet', 0, 0), 
(14, 'dfdf', 'holdet2', 0, 0), 
(15, 'hest', 'tervej', 2, 3), 
(16, 'hestener', 'marksvej', 0, 0), 
(17, 'holdet2', 'holdet', 0, 0), 
(18, 'Odensevej', 'marksvej', 0, 0), 
(19, 'hest', 'dfdf', 0, 0), 
(20, 'tervej', 'hestener', 0, 0), 
(21, 'hest', 'holdet', 0, 0), 
(22, 'marksvej', 'holdet2', 0, 0), 
(23, 'tervej', 'Odensevej', 0, 0), 
(24, 'dfdf', 'hestener', 0, 0), 
(25, 'holdet', 'hestener', 0, 0), 
(26, 'hest', 'marksvej', 0, 0), 
(27, 'tervej', 'holdet2', 0, 0), 
(28, 'Odensevej', 'dfdf', 3, 2);

HOLD

INSERT INTO `hold` (`id`, `hold`, `leder`, `telefon`, `email`, `fgoal`, `agoal`, `p`) VALUES 
(6, 'holdet', 'kim anov', '345345', '[email protected]', 0, 0, 0), 
(20, 'marksvej', 'svend dellepude', '345345', '[email protected]', 0, 0, 1), 
(61, 'tervej', 'Kim Test', '34343434', '[email protected]', 0, 0, 1), 
(64, 'dfdf', 'dfdf', 'dfdf', '[email protected]', 0, 0, 0), 
(67, 'Odensevej', 'Brian Anov', '34343434', '[email protected]', 3, 2, 2), 
(69, 'holdet2', 'asda asdasd', '4234234', '[email protected]', 0, 0, 0), 
(70, 'hest', 'kim a', '323423', '[email protected]', 0, 0, 0), 
(71, 'hestener', 'asdasd asdasd', '3423423423', 'safsdfasdasd.com', 0, 0, 2);

來源

2014-10-29 Kim Anov

問題是什麼？：？ – KingCrunch 2014-10-29 14:10:11

**如何**這不適合你？ – 2014-10-29 14:10:49

它只從kampe最後一行插入數據來保存。不明白爲什麼它不循環，並將所有值插入不同的保留。 – 2014-10-29 14:17:21

這並不直接回答你關於爲什麼你的查詢結果的循環失敗，你的問題，但是......沒有理由你應該在PHP中循環來做到這一點。一個查詢會執行兩個SELECT和UPDATE：

update hold h 
left join kampe k on 
    k.hold1 = h.hold 
set 
    fgoal = k.hold1goal, 
    agoal = k.hold2goal

添加一個PHP循環到混合極大地增加你的開銷是什麼在你的數據庫相對簡單UPDATE查詢。

來源

2014-10-29 14:19:29 JNevill

幾乎工作。一場比賽沒有註冊。使用$ stmt = $ db-> prepare（「UPDATE hold h LEFT JOIN kampe k ON k.hold1 = h.hold SET fgoal = k.hold1goal，agoal = k.hold2goal」）; $ stmt->執行（）; – 2014-10-29 15:31:05

您可能想要檢查該遊戲是否出現在類似的SELECT語句中：'SELECT * FROM hold h LEFT JOIN kampe k on k.hold1 = h.hold'如果它不在那裏，或者kampe值爲NULL，那麼它意味着那'kampe'沒有那個'hold'記錄的值。 – JNevill 2014-10-29 15:38:20

foreach循環中的更新表

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