SQL：按語句顯示相同的值？

Question

我有這樣的SQL代碼：

select count(req_id), SUBMITS from requests where result='REJECT' GROUP BY SUBMITS 

我得到的輸出是：

1 16-JUN-17 
1 19-JUN-17 
1 16-JUN-17 
1 16-JUN-17 

，而我想：

3 16-JUN-2017 
1 19-JUN-2017 

Answer 1

你可能有小時，分鐘，秒您的工具未顯示給您的SUBMITS列;這樣，您認爲所有行具有相同的SUBMITS值，但它們只有相同的日期，但時間不同。

如果是這樣，您只需將信息限制在一個日期，但不小時，分鐘和秒：

select count(req_id), trunc(SUBMITS) 
from requests 
where result='REJECT' 
GROUP BY trunc(SUBMITS) 

例如：

SQL> create table requests (submits date, result VARCHAR2(10), req_id NUMBER); 

Table created. 

SQL> insert into requests (req_id, submits, result) values (1, sysdate, 'REJECT'); 

1 row created. 

SQL> insert into requests (req_id, submits, result) values (2, sysdate, 'REJECT'); 

1 row created. 

SQL> insert into requests (req_id, submits, result) values (3, sysdate, 'REJECT'); 

1 row created.  

SQL> select count(req_id), trunc(SUBMITS) 
    2 from requests 
    3 where result='REJECT' 
    4 GROUP BY trunc(SUBMITS); 

COUNT(REQ_ID) TRUNC(SUB 
------------- --------- 
      3 21-JUN-17 

SQL> select count(req_id), SUBMITS 
    2 from requests 
    3 where result='REJECT' 
    4 GROUP BY SUBMITS; 

COUNT(REQ_ID) SUBMITS 
------------- --------- 
      1 21-JUN-17 
      1 21-JUN-17 
      1 21-JUN-17