是否可以使用「聚合和組合兩個查詢」組合（結果集）？

Question

Select id,count(*) as totalX FROM my_table WHERE x_factor = 1 GROUP BY id 

結果集：

id  totalX 
--------- -------------- 
     9    34 
     10    6 
     11    21 
     12    3 

Select id,count(*) as totalY FROM my_table WHERE y_factor = 1 GROUP BY id 

結果集2：

id  totalY 
--------- -------------- 
     9    334 
     10    56 
     11    251 
     12    93 

有沒有一種方法，我可以做到這一點：

id  totalX  totalY   
--------- -------------- -------------- 
     9    34    334 
     10    6    56 
     11    21    251 
     12    3    93 

我想爲Sybase 12.5的解決方案在RHEL 5，我也想知道這是否可能在任何其他數據庫系統。

---謝謝你的答案（S） - 基於真/假的，你可以在這兩個

Comparing EXECUTION TIME: (For a certain query) 
Query 1: 
Execution Time 61. 
SQL Server cpu time: 6100 ms. SQL Server elapsed time: 12133 ms. 

Query 2: 
Execution Time 53. 
SQL Server cpu time: 5300 ms. SQL Server elapsed time: 12090 ms. 

Query X(1+2): 
Execution Time 84. 
SQL Server cpu time: 8400 ms. SQL Server elapsed time: 21456 ms. 

Answer 1

通過使用CASE/WHEN爲列，總結1或0同樣的查詢......此外，你可以做同樣的事情，如果你想在另一列中的某些值的總和......剛剛替補，對於真正的價值，而不是1

select 
     id, 
     sum(CASE WHEN x_factor = 1 THEN 1 ELSE 0 END) as X_Count, 
     sum(CASE WHEN y_factor = 1 THEN 1 ELSE 0 END) as Y_Count 
    from 
     yourTable 
    group by 
     id 

Answer 2

這應該工作：

SELECT id, 
     sum(case when x_factor = 1 then 1 else 0 end) as totalX, 
     sum(case when y_factor = 1 then 1 else 0 end) as totalY 
    FROM my_table 
    WHERE x_factor = 1 
     OR y_factor = 1 
    GROUP BY id 

Answer 3

CASE ... {0 | 1}對於人們來說是一個很好的竅門，但我認爲這個問題可能比這更簡單。您是否嘗試過：

SELECT id, COUNT(x_factor) AS count_x, COUNT(y_factor) AS count_y FROM my_table GROUP BY id