2012-12-06 35 views
0

這裏的data.frame問題:爲什麼我不能聚集data.frame與FUN = shapiro.test

sample <- dput(df) 
structure(c(6, 5, 5, 4, 4, 7, 5, 4, 6, 6, 5, 6, 8, 6, 3, 5, 8, 
4, 7, 6, 4, 4, 2, 5, 4, 7, 2, 5, 5, 4, 6, 4, 5, 8, 6, 4, 7, 7, 
4, 4, 5, 8, 4, 6, 9, 3, 7, 6, 8, 6, 6, 3, 3, 6, 7, 7, 6, 6, 7, 
7, 6, 7, 8, 3, 5, 5, 4, 6, 4, 7, 3, 4, 6, 3, 5, 5, 7, 6, 7, 4, 
3, 5, 4, 5, 3, 6, 8, 6, 4, 9, 8, 5, 4, 7, 4, 6, 7, 5, 6, 9, 7, 
6, 8, 5, 0, 5, 6, 5, 7, 5, 5, 7, 2, 5, 7, 4, 3, 7, 7, 6, 7, 8, 
5, 6, 9, 4, 6, 7, 5, 4, 5, 4, 6, 6, 9, 8, 5, 7, 7, 7, 4, 7, 6, 
7, 6, 9, 5, 4, 8, 4, 6, 4, 6, 0, 4, 7, 6, 4, 6, 3, 0, 3, 4, 5, 
8, 5, 6, 6, 5, 5, 7, 7, 5, 7, 8, 3, 4, 4, 5, 7, 5, 8, 6, 9, 7, 
5, 4, 3, 4, 4, 6, 2, 4, 6, 7, 6, 5, 5, 5, 5, 6, 6, 8, 5, 5, 6, 
6, 4, 5, 8, 4, 7, 5, 6, 3, 6, 5, 3, 6, 3, 6, 6, 7, 4, 2, 6, 5, 
4, 5, 6, 6, 6, 7, 6, 6, 6, 5, 6, 5, 6, 6, 7, 7, 6, 6, 5, 5, 5, 
7, 6, 9, 8, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 
1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 
1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 
1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 
1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 
2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 
2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 
2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 
2, 2, 2, 2, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 
3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 
3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 
3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 
3, 3, 3, 3), .Dim = c(252L, 2L), .Dimnames = list(NULL, c("pMRMW", 
"group"))) 

aggregate(pMRMW~group,data=sample,shapiro.test) 

回報

corrupt data frame: columns will be truncated or padded with NAs 

其它功能按預期工作。

我錯過了一些完全明顯的東西嗎?

回答

3

問題發生是因爲shapiro.test()返回4個值的列表。

如果您需要的p值,那麼你可以做

aggregate(pMRMW~group,data=sample,function (x) shapiro.test(x)$p.value) 
    group  pMRMW 
1  1 0.0064932854 
2  2 0.0006112324 
3  3 0.0044895909 
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