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讓說,我有一個包含該數據學生信息系統級分配矢量搜索
First Name Last Name ID Tuition GPA
Alex Robinson 02341 1400.50 3.45
John Brown 043261 1200.00 3.21
Rachel VanGorp 77239 600.00 4.00
James Smith 89167 1150.55 1.45
Juan Garcia 23165 1200.00 3.33
Lindsey McDonald 32501 1340.50 2.25
Tom Barry 78442 500.00 3.85
Gwen Poss 30029 1150.50 3.85
Janice Jones 44560 2200.50 2.45
Jack Price 99314 1850.55 3.12
一個文本文件,我導入項目名單爲載體,這裏是我的學生類和我classOfStudents類。幫助這個信息將是偉大的。我迷路了,不知道該去哪裏。只有參考和一個正確的方向點將是偉大的!
class student
{
public:
student()
{
firstName = "";
lastName = "";
ID = "";
tuitionBalance = 0.0;
GPA = 0.0;
}
student(string first, string last, string id, double tuition, double gpa)
{
first = firstName;
last = lastName;
id = ID;
tuition = tuitionBalance;
gpa = GPA;
}
void openIF()
{
inFile.open("students.txt");
}
void setFirstName()
{
inFile >> temp;
firstName = temp;
}
void setLastName()
{
inFile >> temp;
lastName = temp;
}
void setID()
{
inFile >> temp;
ID = temp;
}
void setBalance()
{
inFile >> tuitionBalance;
}
void setGPA()
{
inFile >> GPA;
}
void closeIF()
{
inFile.close();
}
string firstName, lastName, ID;
double tuitionBalance, GPA;
private:
ifstream inFile;
char temp[128];
}
class classOfStudents
{
public:
vector<student> students;
classOfStudents()
{
student Students = student(firstName, lastName, ID, tuitionBalance, GPA);
students.push_back(Students);
}
void findStudent()
{
int searchID;
cout << "Enter ID of student" << endl;
cin >> searchID;
find(students.begin(), students.end(), searchID);
}
private:
string firstName, lastName, ID;
double tuitionBalance, GPA;
}
我怎麼會拉與學生的只是ID
其餘的信息?
你可以用'ID'作爲鍵和'student'作爲'map'作爲值。 – CoryKramer
最基本的解決方案是迭代矢量,直到找到具有正確ID的「學生」;網絡方法用於開始使用更復雜的數據結構(一點點)。 – SJuan76
@Cyber當我試圖映射它時Visual Studio告訴我,我在地圖 – user3658110