我無法在pygame中得到我的碰撞代碼

我的碰撞代碼確實是錯誤的，因爲紅色的「子彈」必須擊中玩家的中間才能在屏幕上運行遊戲。我需要幫助重構表達，所以如果紅色的「子彈」擊中玩家的任何地方它會運行我的遊戲結束代碼（代碼上的遊戲已經接近尾聲pygame.quit（）之前）我無法在pygame中得到我的碰撞代碼

import pygame 
import random 
BLACK = (0,0,0) 
WHITE = (255,255,255) 
GREEN = (0,255,0) 
RED = (255,0,0) 
BLUE = (0,0,255) 
pygame.init() 
size = (700,700) 
screen = pygame.display.set_mode(size) 
pygame.display.set_caption("Dodger") 
done = False 
clock = pygame.time.Clock() 

def resetpositions(): 
    global bulletrect1, bulletrect2, bulletrect3, bulletrect4, bulletrect5, circlerect 
    bulletrect1 = pygame.rect.Rect((350, 0, 20, 20)) 
    bulletrect2 = pygame.rect.Rect((175, 0, 20, 20)) 
    bulletrect3 = pygame.rect.Rect((525, 0, 20, 20)) 
    bulletrect4 = pygame.rect.Rect((525, 0, 20, 20)) 
    bulletrect5 = pygame.rect.Rect((525, 0, 20, 20)) 

circlerect = pygame.rect.Rect((350, 600, 20, 20)) 

resetpositions() 
while not done: 
    for event in pygame.event.get(): 
     if event.type == pygame.QUIT: 
      done = True 
     if event.type == pygame.KEYDOWN: 
      circlerect.x += 5 
    bulletrect1.y += 1 
    bulletrect2.y += 2 
    bulletrect3.y += 3 
    bulletrect4.y += 4 
    bulletrect5.y += 5 
    screen.fill(BLACK) 
    pygame.draw.circle(screen, GREEN, (circlerect.center), 15) 
    pygame.draw.circle(screen, RED, (bulletrect1.center), 20) 
    pygame.draw.circle(screen, RED, (bulletrect2.center), 20) 
    pygame.draw.circle(screen, RED, (bulletrect3.center), 20) 
    pygame.draw.circle(screen, RED, (bulletrect4.center), 20) 
    pygame.draw.circle(screen, RED, (bulletrect5.center), 20) 
    if bulletrect1.y == 800: 
     bulletrect1.y = 0 
     bulletrect1.x = random.randint(20,680) 
    if bulletrect2.y == 800: 
     bulletrect2.y = 0 
     bulletrect2.x = random.randint(20,680) 
    if bulletrect3.y == 800: 
     bulletrect3.y = 0 
     bulletrect3.x = random.randint(20,680) 
    if bulletrect4.y == 800: 
     bulletrect4.y = 0 
     bulletrect4.x = random.randint(20,680) 
    if bulletrect5.y == 800: 
     bulletrect5.y = 0 
     bulletrect5.x = random.randint(20,680) 
    if circlerect.x == 685: 
     circlerect.x = 15 
    if circlerect.collidelist((bulletrect1, bulletrect2, bulletrect3, bulletrect4, bulletrect5)) == 0: 
     screen.fill(BLACK) 
     font = pygame.font.SysFont('Calibri',40,True,False) 
     text = font.render("GAME OVER",True,RED) 
     screen.blit(text,[250,350]) 
     pygame.display.update() 
     pygame.time.delay(3000) 
     resetpositions() 
    pygame.display.flip() 
    clock.tick(300) 
pygame.quit()

來源

2017-09-26 Billy Bob

它是安全的假設你所有的物體可以視爲圈子？如果是這樣，你可以檢查給定子彈（紅色圓圈）和玩家（綠色圓圈）的中心之間的距離是否小於這兩個物體/圓圈的半徑之和。 – CodeSurgeon

pygame.Rect.collidelist返回列表中碰撞矩陣的索引，這意味着您只檢查circlerect是否與索引0上的子彈相沖突。它返回-1如果列表中沒有rects發生碰撞，因此，如果它不返回-1的rects的一個人相撞玩家和遊戲結束：

if circlerect.collidelist((bulletrect1, bulletrect2, bulletrect3, bulletrect4, bulletrect5)) != -1: 
    # Game over.

來源

2017-09-26 10:58:34 skrx

請註冊並接受有幫助的答案，將其標記爲已解決。接受答案也會給你2點聲望點。 – skrx

我無法在pygame中得到我的碰撞代碼

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