完全以90度間隔旋轉

我有一個圓形菜單，每旋轉90度左右leftArrow_mc被點擊，但在270度時按鈕停止工作。將度數重設爲0也可以爲我做任何事情嗎？完全以90度間隔旋轉

import com.greensock.*; 
    import com.greensock.easing.*; 

    leftArrow_mc.addEventListener(MouseEvent.CLICK, rotateLeft1); 

    function rotateLeft1(event: MouseEvent):void { 
if (bottomWheel_menu_mc.rotation==0) { 
    TweenLite.to(bottomWheel_menu_mc, 1, {rotation: 90, ease:Bounce.easeOut}); 
} else if (bottomWheel_menu_mc.rotation == 90) { 
    TweenLite.to(bottomWheel_menu_mc, 1, {rotation: 180, ease:Bounce.easeOut}); 
} else if (bottomWheel_menu_mc.rotation == 180) { 
    TweenLite.to(bottomWheel_menu_mc, 1, {rotation: 270, ease:Bounce.easeOut}); 
} else if (bottomWheel_menu_mc.rotation == 270) { 
    TweenLite.to(bottomWheel_menu_mc, 1, {rotation: 360, ease:Bounce.easeOut}); 
} 
else if (bottomWheel_menu_mc.rotation == 360) { 
    bottomWheel_menu_mc.rotation == 0 
}

}

來源

2013-08-29 Tyler Richardson

應注意：如果答案可以幫助解決你的問題，你應該接受的答案，或者人們將不太可能幫助你.. – joshua

繼承人你的答案，它的工作原理。如果你需要的工作讓我know..its遲到這樣的IM不知道爲什麼這行爲就像它，但我會檢查進入地產（旋轉:)在你的補間內。

 import com.greensock.*; 
     import com.greensock.easing.*; 

    leftArrow_mc.addEventListener(MouseEvent.CLICK, rotateLeft1); 

    function rotateLeft1(event: MouseEvent):void { 
     if (bottomWheel_menu_mc.rotation==0) { 
     TweenLite.to(bottomWheel_menu_mc, 1, {rotation: 90, ease:Bounce.easeOut}); 
     } else if (bottomWheel_menu_mc.rotation == 90) { 
     TweenLite.to(bottomWheel_menu_mc, 1, {rotation: 180, ease:Bounce.easeOut}); 
     } else if (bottomWheel_menu_mc.rotation == 180) { 
     TweenLite.to(bottomWheel_menu_mc, 1, {rotation: 270, ease:Bounce.easeOut}); 
     } else if (bottomWheel_menu_mc.rotation == -90) { 
     TweenLite.to(bottomWheel_menu_mc, 1, {rotation: 0, ease:Bounce.easeOut}); 
     } 
     trace(bottomWheel_menu_mc.rotation); 
    }

來源

2013-08-30 14:35:16 joshua

非常感謝！完美的作品！動作不允許超過270度的值？現在我試圖用右箭頭創建相同的腳本（逆時針轉動）。即時通訊得到類似的問題。我要去： 0 - > - 90 270-> 180 180-> 90 90-> 0 –

在理論上應該是oppisite ... – joshua

但我做了同樣的事情，你只是在反向 –

完全以90度間隔旋轉

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