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我試圖在Socket.io v.7中使用新的「房間」功能來創建動態聊天室,但我在獲取靜態房間時遇到問題。根據用戶選擇的URL,它們應該在room1或room2中結束。用戶在聊天中輸入的任何內容都應廣播給同一個房間的用戶。我有兩個瀏覽器(chrome & ff),每個瀏覽器都有一個打開/ room1和/ room2的選項卡,但是我輸入的任何東西似乎都不會播放到其他選項卡。我究竟做錯了什麼?帶有Socket.io和節點的動態房間
Server代碼
var app = require('express').createServer();
var io = require("socket.io").listen(app);
io.sockets.on('connection', function (socket) {
// join to room and save the room name
socket.on('join room', function (room) {
socket.set('room', room, function() { console.log('room ' + room + ' saved'); });
socket.join(room);
})
socket.on('message', function(data) {
console.log("Client data: " + data);
// lookup room and broadcast to that room
socket.get('room', function(err, room) {
//room example - https://github.com/learnboost/socket.io
// neither method works for me
socket.broadcast.to(room).emit('new fan');
io.sockets.in(room).emit('new non-fan');
})
})
});
app.get('/room1', function(req, res){
res.render('example2-client.ejs', {layout:false});
});
app.get('/room2', function(req, res){
res.render('example2-client-2.ejs', {layout:false});
});
app.listen(4000);
客戶端代碼室1
<!DOCTYPE HTML>
<html><head>
<title>Code review for Snipet</title>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.4/jquery.min.js"></script>
<script type="text/javascript" src="http://localhost:4000/socket.io/socket.io.js"></script>
<script>
$(document).ready(function() {
var socket = io.connect('http://localhost:4000');
$("#msgbox").keypress(function(event) {
if (event.which == '13') {
sendmsg();
event.preventDefault();
}
});
socket.on('connect', function (data) {
socket.emit('join room', 'room1');
});
socket.on('message', function (data) {
add_message(data);
});
function add_message(m) {
$("#chatlog").append(m);
$("#chatlog").append("<BR>");
}
function sendmsg()
{
var r = $("#msgbox").val();
socket.emit('message', r);
add_message(r);
$("#msgbox").val('');
}
});
</script>
</head>
<body>
<div id="chat" style="height: 200px; width: 200px; border: 1px solid grey;">
<div id="chatlog" style="height: 178px; width: 200px; overflow-y: scroll;"></div>
<input type="text" id="msgbox" style="margin-left: 2px; width: 193px;">
</div>
</body>
</html>
客戶端代碼2
<!DOCTYPE HTML>
<html><head>
<title>Code review for Snipet</title>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.4/jquery.min.js"></script>
<script type="text/javascript" src="http://localhost:4000/socket.io/socket.io.js"></script>
<script>
$(document).ready(function() {
var socket = io.connect('http://localhost:4000');
$("#msgbox").keypress(function(event) {
if (event.which == '13') {
sendmsg();
event.preventDefault();
}
});
socket.on('connect', function (data) {
socket.emit('join room', 'room2');
});
socket.on('message', function (data) {
add_message(data);
});
function add_message(m) {
$("#chatlog").append(m);
$("#chatlog").append("<BR>");
}
function sendmsg()
{
var r = $("#msgbox").val();
socket.emit('message', r);
add_message(r);
$("#msgbox").val('');
}
});
</script>
</head>
<body>
<div id="chat" style="height: 200px; width: 200px; border: 1px solid grey;">
<div id="chatlog" style="height: 178px; width: 200px; overflow-y: scroll;"></div>
<input type="text" id="msgbox" style="margin-left: 2px; width: 193px;">
</div>
</body>
</html>
我雖然該客戶會從服務器接收的所有消息在socket.on(「信息」,...函數? 其實我正在發送消息給客戶端。在上面的示例中,我從發送客戶端收到消息,查找房間並試圖調用socket.broadcast.to(room).emit('some文字') – Rick
你的客戶正在收聽socket.on('message'...),但你的服務器沒有發出'信息' 您需要將「io.sockets.in(room).emit('message',data);」添加到您的服務器代碼中。 –
在工作的服務器上添加通道「消息」。謝謝。 – Rick