爲什麼PlayerInteractEvent不適用於Bukkit API？

所以，我正在使用Bukkit API。基本上，我正在尋找被調用的PlayerInteractEvent，然後我做了一堆事情。但是，當我得到通知我實際上已經踢掉了該塊時，即使它在我的代碼中編譯沒有錯誤，我也沒有收到任何消息。我也沒有從控制檯獲得例外。這裏是我的代碼：爲什麼PlayerInteractEvent不適用於Bukkit API？

@EventHandler(priority=EventPriority.HIGH) 
public void onPlayerInteract(PlayerInteractEvent event, final Player who, final Action action, 
     final ItemStack item, final Block clickedBlock, final BlockFace clickedFace) { 

    if (who != null) { 

     if (clickedBlock != null) { 

      if ((action == Action.LEFT_CLICK_BLOCK) && (clickedBlock.getType() == Material.ANVIL)) { 

       if (item == null) { 

        who.sendMessage(ChatColor.YELLOW + "To repair an item, hold it in your inventory and " + 
          ChatColor.UNDERLINE + "RIGHT CLICK" + ChatColor.RESET + "" + ChatColor.YELLOW + 
          " the anvil with the item."); 

        event.setCancelled(true); 

       } 
       else { 

        Material type = item.getType(); 
        short durability = item.getDurability(); 
        short maximum = type.getMaxDurability(); 

        if (maximum == 0) { 

         who.sendMessage(ChatColor.RED + "You can " + ChatColor.UNDERLINE + "NOT" + 
           ChatColor.RESET + "" + ChatColor.RED + " repair that item."); 

        } 
        else { 

         short add = (short) Math.round(maximum * 0.03); 

         int result = (maximum - durability)/add; 

         int gems = getAmount(who, 388); 

         if (gems < result) { 

          who.sendMessage(ChatColor.RED + "You do " + ChatColor.UNDERLINE + "NOT" + 
            ChatColor.RESET + "" + ChatColor.RED + " have enough Gems to repair " 
            + "that item."); 
          who.sendMessage(ChatColor.RED + "" + ChatColor.BOLD + "Gems Needed: " + result); 

         } 
         else { 

          who.sendMessage(ChatColor.YELLOW + "It will cost " + ChatColor.WHITE + 
            result + "g " + ChatColor.GREEN + "to repair this item."); 
          who.sendMessage(ChatColor.YELLOW + "Continue repairing? " + ChatColor.GREEN + 
            "" + ChatColor.BOLD + "Y" + ChatColor.RESET + "" + ChatColor.WHITE + 
            "/" + ChatColor.RESET + "" + ChatColor.RED + "" + ChatColor.BOLD + 
            "N"); 

          map.put(who, item); 

         } 

        } 

       } 

      } 

     } 

    } 

}

來源

2013-08-02 user2646941

因此，要做到這一點的標準方法是在你創建的

@EventHandler 
public void nameDontMatter(PlayerInteractEvent event) { 
// do stuff, you can get all that information you passed in from the event 

}

形式方法也需要創建一個類，implements Listener

然後一定要告訴插件在哪裏找到您的PlayerListener，因此通常您要做的是在onEnable()方法中您將會放置：

PlayerListenerClass PL = new PlayerListenerClass(); 
//instantiate an instance of you player listener 

public void onEnable() { 
    PluginManager pm = this.getServer().getPluginManager(); 
    pm.registerEvents(InspiredNationsPL, this); 
    //Tell the plugin manager where it can find the player listener 
}

這應該讓它工作。

來源

2013-08-02 22:21:37 Kammeot

我已經這樣做了，所以我不確定還有什麼可能是問題。 – user2646941

該方法的唯一參數是PlayerIneractEvent。您無法在此處設置更多參數。

您已經設置了比方法本身更多的參數。

@EventHandler 
public void onPlayerInteract(PlayerInteractEvent event, Player who, ...) { 
    ... 
}

用這個代替：

@EventHandler 
public void onPlayerInteract(PlayerInteractEvent event) { 
    // do stuff here 
}

裏面的方法，你可以得到所有你作爲參數設定其他的事情。例如：

event.getPlayer(); // gets the player 
event.getAction(); // gets the action

另請注意，您已將您的監聽器註冊到您的插件主類中。

registerEventHandler(yourEventHandler, this);

來源

2013-08-15 14:57:50 bw2801

你只能有PlayerInteractEvent，否則它不會工作。此外，您不需要提供播放器作爲參數，您可以使用getPlayer（）方法查看誰觸發了該事件。

@EventHandler 
public void onPlayerInteract(PlayerInteractEvent e) { 
Player player = e.getPlayer(); 
}

來源

2013-09-12 00:10:53

爲什麼PlayerInteractEvent不適用於Bukkit API？

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