1
#include <iostream>
#include <mutex>
using namespace std;
int main()
{
mutex m;
m.lock();
cout << "locked once\n";
m.lock();
cout << "locked twice\n";
return 0;
}
./a.out
locked once
locked twice
不程序需要在第二鎖定即互斥的點死鎖由同一線程被鎖定兩次?