我寫這樣一個素文字: #!/bin/bash
while read line
do
echo line ${line}
pdbfile=${line}.pdb
echo pdbfile ${pdbfile}
done < myfile
結果是: line pdb8mhtA
.pdbfile pdb8mhtA
雖然它被認爲是 line pdb8mhtA
這裏就是我想要做的事: String output = "If you borrow" + currencyFormatter.format(loanAmount);
+" at an interest rate of" + rate + %;
+"\nfor" + years;
+",you will pay" + totalInterest + "in inter
我試着這樣做: select * into 'DataBackup'+convert(varchar(10),getdate(),112)+'byMike' from SomeTable
但它返回一個錯誤。我也試過這一個,但無濟於事: select * into
(select 'DataBackup'+convert(varchar(10),getdate(),112)+'byMike')
假設一個數據幀包含 attacker_1 attacker_2 attacker_3 attacker_4
Lannister nan nan nan
nan Stark greyjoy nan
我想創建一個名爲AttackerCombo另一列是聚合了4列到1列結合起來。 我將如何去在python中定義這樣的代碼? 我已經練習Python和我認爲這種列表解析是有意義的,但[
我不想匹配jess-object的值(字符串),而比較值是字符串和另一個字段的組合。 這裏一個簡單的( 「可運行」)例如: (defclass Person (is-a :THING) (slot name (type string)) (slot email (type string)))
(mapclass Person)
(make-instance Andy of Person (n