-6
編寫代碼來模擬一名玩家的遊戲並計算完成遊戲所需的擲骰子數。應該允許用戶指定模擬的遊戲數量,並且代碼應該計算每場遊戲擲骰子的平均數量。如何退出while循環 - 當counterPosition> = 100時開始新遊戲
import random
def diceRoll():
return random.randint (1,6)
userInput = int(input("How many games would you like to play snakes and ladders?"))
totalDiceRolls = 0
for i in range(userInput):
counterPosition = 0
while (counterPosition < 100):
totalDiceRolls += 1
currentDiceRoll = diceRoll()
counterPosition += currentDiceRoll
if counterPosition == 1:
counterPosition = counterPosition + 37
if counterPosition == 4:
counterPosition = counterPosition + 10
if counterPosition == 9:
counterPosition = counterPosition + 22
if counterPosition == 21:
counterPosition = counterPosition + 21
if counterPosition == 28:
counterPosition = counterPosition + 56
if counterPosition == 51:
counterPosition = counterPosition + 16
if counterPosition == 72:
counterPosition = counterPosition + 19
if counterPosition == 80:
counterPosition = counterPosition + 19
if counterPosition == 17:
counterPosition = counterPosition - 10
if counterPosition == 54:
counterPosition = counterPosition - 20
if counterPosition == 63:
counterPosition = counterPosition - 4
if counterPosition == 64:
counterPosition = counterPosition - 4
if counterPosition == 87:
counterPosition = counterPosition - 51
if counterPosition == 92:
counterPosition = counterPosition - 19
if counterPosition == 95:
counterPosition = counterPosition - 20
if counterPosition == 98:
counterPosition = counterPosition - 19
if counterPosition >= 100:
avgRolls = totalDiceRolls/userInput
print("The average number of rolls per game is", avgRolls)
這個確切的問題不僅僅是在半小時前問過的嗎? – Tagc
是啊哈哈還是不能找出來 – Ben
好吧,playGame不會返回任何東西,所以將其結果添加到數字中是沒有意義的。 – Carcigenicate