如何在同一結果表中包含來自兩個查詢的信息？

Question

我有以下疑問：

select year, avg(value) as winter_avg_Miami from AP_DATA where substring(series_id, 8) ='killowatts' and substring(series_id, 3,5) = 'Miami' and period IN ('M10','M11','M12') group by year; 
select year, avg(value) as winter_avg_notMiami from AP_DATA where substring(series_id, 8) = 'killowatts' and substring(series_id, 3,5) != 'Miami' and period IN ('M10','M11','M12') group by year; 

我想要做的是不是得到兩個不同的表，一個像：

year  winter_avg_Miami 
2000    28.1 
2001    30.2 

和另一個表所示：

year  winter_avg_notMiami 
2000    40.1 
2001    50.2 

我想只是在一張表中包含所有信息，例如：

year  winter_avg_Miami winter_avg_notMiami 
2000    28.1    40.1 
2001    30.2    50.2 

如何編寫我的查詢以完成此操作？

Answer 1

您可以在avg骨料使用case聲明：

select year, 
    avg(case when substring(series_id, 3,5) = 'Miami' then value end) as winter_avg_Miami, 
    avg(case when substring(series_id, 3,5) != 'Miami' then value end) as winter_avg_notMiami 
from AP_DATA 
where substring(series_id, 8) ='killowatts' 
    and period IN ('M10','M11','M12') 
group by year 

• Condensed SQL Fiddle Demo

Answer 2

select 
     year, 
     case when CntMiami = 0 then 0 else TotMiami/CntMiami end) as AvgMiami, 
     case when CntNotMiami = 0 then 0 else TotNotMiami/CntNotMiamt end) as AvgNotMiami 
from 
    (
select 
     year, 
     sum(case when substring(series_id, 3,5) = 'Miami' then value else 0 end) as TotMiami, 
     sum(case when substring(series_id, 3,5) = 'Miami' then 1 else 0 end) as CntMiami, 
     sum(case when substring(series_id, 3,5) != 'Miami' then value else 0 end) as TotNotMiami, 
     sum(case when substring(series_id, 3,5) != 'Miami' then 1 else 0 end) as CntNotMiami 
    from 
     AP_DATA 
    where 
      substring(series_id, 8) ='killowatts' 
     and period IN ('M10','M11','M12') 
    group by 
     year) 

Answer 3

如果你的查詢都是正確的，這應該工作：

SELECT a.year, a.winter_avg_Miami, b.winter_avg_notMiami 
From (select year, avg(value) as winter_avg_Miami 
    from AP_DATA where substring(series_id, 8) ='killowatts' and 
     substring(series_id, 3,5) = 'Miami' and period IN ('M10','M11','M12') 
    group by year)a, 
    (select year, avg(value) as winter_avg_notMiami 
    from AP_DATA where substring(series_id, 8) = 'killowatts' and 
    substring(series_id, 3,5) != 'Miami' and period IN ('M10','M11','M12') 
    group by year) b 
WHERE a.year = b.year; 

Answer 4

UNIONS是一個簡單的選擇，如果有一些原因，你不能做像sgeddes建議更傳統的方式之一。

Answer 5

請嘗試以下解決方案：

解決方案：1

select ap1.year, avg(ap1.value) as winter_avg_Miami,avg(ap2.value) as winter_avg_notMiami 
 
from AP_DATA ap1 left join ap2.AP_DATA on ap1.year=ap2.year 
 
where substring(ap1.series_id, 8) ='killowatts' and substring(ap1.series_id, 3,5) = 'Miami' and ap1.period IN ('M10','M11','M12') 
 
substring(ap2.series_id, 8) = 'killowatts' and substring(ap2.series_id, 3,5) != 'Miami'and ap2.period IN ('M10','M11','M12') 
 
group by ap1.year;

解決方案：2

--create temp table 
 
create table temp1 
 
(year int, winter_avg_Miami int null,winter_avg_notMiami int null) 
 

 
--insert into temp table 
 
insert into temp1 
 
(year int, winter_avg_Miami ,winter_avg_notMiami) 
 
(
 
select year, avg(value) as winter_avg_Miami,null as winter_avg_notMiami from AP_DATA where substring(series_id, 8) ='killowatts' and substring(series_id, 3,5) = 'Miami' and period IN ('M10','M11','M12') group by year 
 
union all 
 
select year, null as winter_avg_Miami, avg(value) as winter_avg_notMiami from AP_DATA where substring(series_id, 8) = 'killowatts' and substring(series_id, 3,5) != 'Miami' and period IN ('M10','M11','M12') group by year 
 
) 
 

 
--result in single table 
 
select year,avg(winter_avg_Miami) as winter_avg_Miami,avg(winter_avg_notMiami) as winter_avg_notMiami 
 
from temp1 
 
group by year

我在sybase上面試過了以上的解決方案。它工作得很好。

希望這有助於:)