如何在MATLAB中計算直線和平面之間的角度？

Question

五點A,B,C,D和E以「3」給出。如何計算線D-E與由A，B和C定義的平面之間的夾角？

我明白這個問題，但我不知道如何在MATLAB中進行編程。我是MATLAB新手，所以詳細的信息會非常有幫助。這是我已經試過了，但它給我的錯誤輸出：

point1 = cross(B-A, C-A); 
point2 = cross(D, E); 
point3 = cross(point1, point2); 
point4 = sqrt(A.*A + B.*B + C.*C); 
point5 = sqrt(D.*D + E.*E) 

point6 = point4*point5; 
final = point3/point6 

Answer 1

這裏亞去：

%// normal vector to plane ABC 
N = cross(B-A, C-A); 

%// angle between plane and line, equals pi/2 - angle between D-E and N 
alpha = abs(pi/2 - acos(dot(E-D, N)/norm(N)/norm(E-D))); 

%// you probably want it in degrees: 
alpha = rad2deg(alpha);