如何測試Rect與Rect |衝突的時間Python | Pygame

Question

我知道你可能認爲它有點複製，但事實並非如此。這不是使用類，完全基於pygame而沒有import os。我需要檢測這兩個矩形是否碰撞，並在代碼中用註釋發送信號。

下面是代碼： 的Python：

import pygame, sys, time, random 
from pygame.locals import * 

pygame.init() 

fpsClock = pygame.time.Clock() 


playSurface = pygame.display.set_mode((640, 480)) 
pygame.display.set_caption('Bob the Block goes Skiing') 

redColour = pygame.Color(252, 0, 6) 

blackColour = pygame.Color(0, 0, 0) 
whiteColour = pygame.Color(255, 255, 255) 
greyColour = pygame.Color(150, 150, 150) 
bobPosition = [300,70] 
direction = 'right' 
changeDirection = direction 
pygame.draw.rect(playSurface,redColour,Rect(bobPosition[0], bobPosition[1], 40, 40)) 
pygame.display.flip() 

length = 100 
obstPosition = [100,475] 
while True: 
    if obstPosition[1] < 25: 
     x = random.randint(10,505) 
     obstPosition = [x,475] 
     length += random.randint(1,5) 
    for event in pygame.event.get(): 
     if event.type == QUIT: 
      pygame.quit() 
     elif event.type == KEYDOWN: 
      if event.key == K_RIGHT or event.key == ord('d'): 
       changeDirection = 'right' 
      if event.key == K_LEFT or event.key == ord('a'): 
       changeDirection = 'left' 
      if event.key == K_ESCAPE: 
       pygame.event.post(pygame.event.Event(QUIT)) 
    direction = changeDirection 
    if direction == 'right': 
     bobPosition[0] += 20 
    if direction == 'left': 
     bobPosition[0] -= 20 
    playSurface.fill(blackColour) 
    a = ['one','two','three'] 
    # Creating the obstacle 
    pygame.draw.rect(playSurface,whiteColour,Rect(obstPosition[0], obstPosition[1], length, 20)) 
    obstPosition[1] -= 10 
    # Creating "bob the block" 
    pygame.draw.rect(playSurface,redColour,Rect(bobPosition[0], bobPosition[1], 25, 25)) 
    pygame.display.flip() 
    if bobPosition[0] > 620 or bobPosition[0] < 0: 
     gameOver() 
    if bobPosition[1] > 460 or bobPosition[1] < 0: 
     gameOver() 

    fpsClock.tick(19) 

Answer 1

商店兩個矩形作爲變量，並使用pygame.Rect.colliderect（）來測試，如果他們重疊。

例如：

rect1 = Rect(0,0,100,100) 
rect2 = Rect(90,90,100,100) 

collideTest = rect1.colliderect(rect2)