轉軸列的值是範圍

Question

我試圖創建一個數據透視表來轉換值的範圍。我使用這個總和技巧，但我最近了解到了pivot操作符，並且我試圖將數據轉換爲數據透視表，因爲代碼可能更容易維護。 （我已經改名爲我的表模糊的數據位）

 select consultation_id, 
       sum(case when current_status_id in (3,4,5,9,10,16,17,18,24,25,26) then 1 else 0 end) [Phase1], 
       sum(case when current_status_id in (4,9,10,16,17,18) then 1 else 0 end) [Phase2], 
       sum(case when current_status_id in (10,16,17,18) then 1 else 0 end) [Phase3], 
       sum(case when current_status_id = 24 then 1 else 0 end) [Rejected], 
       sum(case when current_status_id in (17,18) then 1 else 0 end) [Complete]  
     from subject with (NOLOCK,NOWAIT) 
     where ACTIVE_IND = 1 
     group by consultation_id 

任何人有如何做轉換有何建議？

編輯： 基本上，我創建了多少個主題的總和，使它成爲我們磋商的一個階段。這是爲lucene索引構建的聚合，以便我們的用戶可以搜索特定的數據。 這裏是原始表格數據的一個例子，什麼輸出可能看起來像::

select consultation_id, 
       sum(case when current_status_id in (3,4,5,9,10,16,17,18,24,25,26) then 1 else 0 end) [Phase1], 
       sum(case when current_status_id in (4,9,10,16,17,18) then 1 else 0 end) [Phase2], 
       sum(case when current_status_id in (10,16,17,18) then 1 else 0 end) [Phase3], 
       sum(case when current_status_id = 24 then 1 else 0 end) [Rejected], 
       sum(case when current_status_id in (17,18) then 1 else 0 end) [Complete]  
     from (values(1588054,11928257,3,1), 
       (1588054,11928256,10,1), 
       (1588054,11928255,10,1), 
       (1588054,11928254,4,1), 
       (1588052,11928233,2,1), 
       (1588052,11928232,3,0), 
       (1588052,11928231,10,1), 
       (1588052,11928230,18,1), 
       (1588052,11928229,24,1), 
       (1588052,11928228,24,1)) subject (consultation_id,subject_id,current_status_id,active_ind) 
     where ACTIVE_IND = 1 
     group by consultation_id 

Answer 1

如果要將此轉換爲PIVOT，那麼我的建議是創建一個包含id'表S代表每個Phases，您正在試圖確定：

create table phases 
(
    id int, 
    name varchar(10) 
); 

然後你會JOIN你subject表對current_status_id這個新表，這將讓你再PIVOT數據：

select s.consultation_id, 
    p.name 
from subject s 
left join phases p 
    on s.current_status_id = p.id 
where s.ACTIVE_IND = 1 

因此，最終的查詢是：

select * 
from 
(
    select s.consultation_id, 
    p.name 
    from subject s 
    left join phases p 
    on s.current_status_id = p.id 
    where s.ACTIVE_IND = 1 
) src 
pivot 
(
    count(name) 
    for name in ([Phase1], [Phase2], [Phase3], [Rejected], [Complete]) 
) piv; 

見SQL Fiddle with Demo

結果現有的查詢相匹配：

| CONSULTATION_ID | PHASE1 | PHASE2 | PHASE3 | REJECTED | COMPLETE | 
-------------------------------------------------------------------- 
|   1588052 |  4 |  2 |  2 |  2 |  1 | 
|   1588054 |  4 |  3 |  2 |  0 |  0 | 

使用表的好處是，如果你需要更多的current_status_id，那麼你可以將它添加到表中，他們w不需要改變你的查詢就可以被計算在內。