0
考慮下面的公式：求解非線性方程組
eqn1 =
sin(t6)*(cos(t4)*sin(t1) + sin(t4)*(cos(t1)*sin(t2)*sin(t3) - cos(t1)*cos(t2)*cos(t3))) + cos(t6)*(cos(t5)*(sin(t1)*sin(t4) - cos(t4)*(cos(t1)*sin(t2)*sin(t3) - cos(t1)*cos(t2)*cos(t3))) - sin(t5)*(cos(t1)*cos(t2)*sin(t3) + cos(t1)*cos(t3)*sin(t2))) == 1
eqn2 =
cos(t6)*(cos(t4)*sin(t1) + sin(t4)*(cos(t1)*sin(t2)*sin(t3) - cos(t1)*cos(t2)*cos(t3))) - sin(t6)*(cos(t5)*(sin(t1)*sin(t4) - cos(t4)*(cos(t1)*sin(t2)*sin(t3) - cos(t1)*cos(t2)*cos(t3))) - sin(t5)*(cos(t1)*cos(t2)*sin(t3) + cos(t1)*cos(t3)*sin(t2))) == 0
eqn3 =
- sin(t5)*(sin(t1)*sin(t4) - cos(t4)*(cos(t1)*sin(t2)*sin(t3) - cos(t1)*cos(t2)*cos(t3))) - cos(t5)*(cos(t1)*cos(t2)*sin(t3) + cos(t1)*cos(t3)*sin(t2)) == 0
eqn4 =
cos(t1)/100 + (19*cos(t1)*cos(t2))/100 - (21*cos(t1)*sin(t2)*sin(t3))/1000 + (21*cos(t1)*cos(t2)*cos(t3))/1000 - (219*cos(t1)*cos(t2)*sin(t3))/1000 - (219*cos(t1)*cos(t3)*sin(t2))/1000 == 619/1000
eqn5 =
- sin(t6)*(cos(t1)*cos(t4) - sin(t4)*(sin(t1)*sin(t2)*sin(t3) - cos(t2)*cos(t3)*sin(t1))) - cos(t6)*(cos(t5)*(cos(t1)*sin(t4) + cos(t4)*(sin(t1)*sin(t2)*sin(t3) - cos(t2)*cos(t3)*sin(t1))) + sin(t5)*(cos(t2)*sin(t1)*sin(t3) + cos(t3)*sin(t1)*sin(t2))) == 0
eqn6 =
sin(t6)*(cos(t5)*(cos(t1)*sin(t4) + cos(t4)*(sin(t1)*sin(t2)*sin(t3) - cos(t2)*cos(t3)*sin(t1))) + sin(t5)*(cos(t2)*sin(t1)*sin(t3) + cos(t3)*sin(t1)*sin(t2))) - cos(t6)*(cos(t1)*cos(t4) - sin(t4)*(sin(t1)*sin(t2)*sin(t3) - cos(t2)*cos(t3)*sin(t1))) == 1
eqn7 =
sin(t5)*(cos(t1)*sin(t4) + cos(t4)*(sin(t1)*sin(t2)*sin(t3) - cos(t2)*cos(t3)*sin(t1))) - cos(t5)*(cos(t2)*sin(t1)*sin(t3) + cos(t3)*sin(t1)*sin(t2)) == 0
eqn8 =
sin(t1)/100 + (19*cos(t2)*sin(t1))/100 - (219*cos(t2)*sin(t1)*sin(t3))/1000 - (219*cos(t3)*sin(t1)*sin(t2))/1000 - (21*sin(t1)*sin(t2)*sin(t3))/1000 + (21*cos(t2)*cos(t3)*sin(t1))/1000 == 0
eqn9 =
sin(t4)*sin(t6)*(cos(t2)*sin(t3) + cos(t3)*sin(t2)) - cos(t6)*(sin(t5)*(cos(t2)*cos(t3) - sin(t2)*sin(t3)) + cos(t4)*cos(t5)*(cos(t2)*sin(t3) + cos(t3)*sin(t2))) == 0
eqn10 =
sin(t6)*(sin(t5)*(cos(t2)*cos(t3) - sin(t2)*sin(t3)) + cos(t4)*cos(t5)*(cos(t2)*sin(t3) + cos(t3)*sin(t2))) + cos(t6)*sin(t4)*(cos(t2)*sin(t3) + cos(t3)*sin(t2)) == 0
eqn11 =
cos(t4)*sin(t5)*(cos(t2)*sin(t3) + cos(t3)*sin(t2)) - cos(t5)*(cos(t2)*cos(t3) - sin(t2)*sin(t3)) == 1
eqn12 =
(219*sin(t2)*sin(t3))/1000 - (219*cos(t2)*cos(t3))/1000 - (21*cos(t2)*sin(t3))/1000 - (21*cos(t3)*sin(t2))/1000 - (19*sin(t2))/100 == 261/1000
是有可以解決這些方程的功能？
你看過牛頓的非線性系統方法嗎？ –
在matlab中是否有函數，或者我應該用筆和紙自己完成它？ –
我認爲你可以應用牛頓的方法與matlab。雖然我手邊沒有這方面的信息，但如果我們能夠谷歌，那麼它可能會變得很清楚。 –