剛體的夾角旋轉角度

Question

我最近在我的3D遊戲中附加了一個剛體，以便它可以與環境相撞。現在鼠標移動直接旋轉剛體。

#include <BULLET/btBulletDynamicsCommon.h> 

void Rotate(float Pitch, float Yaw, float Roll, float Speed) 
{ 
    // get current rotation 
    btTransform transform = body->getWorldTransform(); 
    btQuaternion rotation = transform.getRotation(); 

    // create orientation vectors 
    btVector3 up(0, 1, 0); 
    btVector3 lookat = quatRotate(rotation, btVector3(0, 0, 1)); 
    btVector3 forward = btVector3(lookat.getX(), 0, lookat.getZ()).normalize(); 
    btVector3 side = btCross(up, forward); 

    // rotate camera with quaternions created from axis and angle 
    rotation = btQuaternion(up,  Amount.getY()) * rotation; 
    rotation = btQuaternion(side, Amount.getX()) * rotation; 
    rotation = btQuaternion(forward, Amount.getZ()) * rotation; 

    // set new rotation 
    transform.setRotation(rotation); 
    body->setWorldTransform(transform); 
} 

我想夾住攝像機的間距的-80°至80°。這有助於玩家保持導向。否則，他將能夠將相機更高地轉動到頭頂上，並將自己背後的世界倒過來看。相反，一個真正的人試圖這會打破他的脖子。

我讓Bullet Physics爲我在四元數存儲旋轉，因此瀝青不直接存儲。我如何夾緊剛體的間距？

Answer 1

我想出了一個解決方案。我不夾緊相機剛體的旋轉，而是夾緊之前施加了多少旋轉。因此，我會跟蹤總的垂直鼠標移動。實際上，我將鼠標的整體移動量存儲爲，並應用了靈敏度。

float Overallpitch = 0.0f; 

如果應用傳遞的偏轉值將導致總體音高超過或deceed給定的極限，我需要接觸到極限只適用儘可能多的它。

#include <BULLET/btBulletDynamicsCommon.h> 

void Rotate(float Pitch, float Yaw, float Roll, float Sensitivity) 
{ 
    // apply mouse sensitivity 
    Yaw *= Sensitivity; 
    Pitch *= Sensitivity; 
    Roll *= Sensitivity; 

    // clamp camera pitch 
    const float clamp = 1.0f; 
    if  (Overallpitch + Pitch > clamp) Pitch = clamp - Overallpitch; 
    else if(Overallpitch + Pitch < -clamp) Pitch = -clamp - Overallpitch; 
    Overallpitch += Pitch; 

    // apply rotation to camera quaternion 
    // ... 
} 

您可以在我自己的問題中找到another answer的更多相機代碼。