Unalignable布爾系列鍵的類型（DF [DF [DF）

Question

我有一個DF和條件DF [DF [ 'EmployeeName'] == 'JOSEPH德里斯科爾']給出以下輸出enter image description here

而當我輸入這個df，可以[DF [ 'EmployeeName'] == 'JOSEPH德里斯科爾'] [ 'BasePay']> 140000
它給出這樣

24真

名稱的輸出：BasePay，D型：布爾

現在我不能ø像這樣

DF [DF [DF [ 'EmployeeName'] == 'JOSEPH德里斯科爾'] [ 'BasePay']> 140000]

並期望輸出與上述圖像相同??

Answer 1

你需要boolean indexing或query與布爾由|（or）創建&（and）或（not）面具，~：

df1 = df[(df['EmployeeName'] == 'JOSEPH DRISCOLL') & (df['BasePay'] > 140000)] 

或者：

df1 = df.query("EmployeeName == 'JOSEPH DRISCOLL' & BasePay > 140000") 

樣品：

df = pd.DataFrame({'EmployeeName':['JOSEPH DRISCOLL','q'],'BasePay':[1000000,10]}) 
print (df) 
    BasePay  EmployeeName 
0 1000000 JOSEPH DRISCOLL 
1  10    q 

print ((df['EmployeeName'] == 'JOSEPH DRISCOLL') & (df['BasePay'] > 140000)) 
0  True 
1 False 
dtype: bool 

df1 = df[(df['EmployeeName'] == 'JOSEPH DRISCOLL') & (df['BasePay'] > 140000)] 
print (df1) 
    BasePay  EmployeeName 
0 1000000 JOSEPH DRISCOLL 

df1 = df.query("EmployeeName == 'JOSEPH DRISCOLL' & BasePay > 140000") 
print (df1) 
    BasePay  EmployeeName 
0 1000000 JOSEPH DRISCOLL