'生日悖論'

Question

我試圖寫一個'生日悖論'的功能。 我在互聯網和succseed中發現了一些例子，將所有的東西結合在一起並進行了一些修改，但仍然存在我在程序中不理解的東西。

這是我的計劃：

# The Birthday Paradox 

print "If there are 23 students in your class, what are the chances that another student and you will have birthday in the same day?" 
print "" 
print "Use the function has_duplicates(numExamples) to check it out!" 
print "Please write in (numExamples) the number of examples of different lists of birthdays of 23-students-classes you want to check." 

def has_duplicates(numExamples): 

import random 
probability = float() 

for example in range(numExamples): 
    year = [0]*365 
    print year 
    foundprobability = False 
    for i in range(23): 
     birthday = random.randrange(365) 
     year[birthday] = year[birthday] + 1 
     if year[birthday]>1: 
      foundprobability = True 

    if foundprobability == True: 
     probability = probability + 1 

countprobabilty = float(probability/numExamples) 
print "The probability of a shared birthday in", numExamples, 
print "examples of different lists of birthdays of 23-students-classes is", countprobabilty 

我不明白這是什麼行表示：

year = [0]*365 

爲什麼我要這樣的列表[0,0,0,0 ... ]？

謝謝！ Netta， 生物學學生

Answer 1

，因爲算法需要365天一年的每一天的計數器，如下：

year[birthday] = year[birthday] + 1 

爲了year[birthday]出現在這個聲明中，它必須先前已經初始化，並且

year = [0] * 365 

初始化它。

Answer 2

year = [0]*365創建具有值0的元素365的列表：[0,0,0,0...]

birthday = random.randrange(365)創建一個列表從0到365和選擇一個隨機元素。
見https://docs.python.org/2/library/random.html#random.randrange