使用在熊貓系列

Question

我有一個熊貓系列在他們。我話的集合列出一串的數量出現想找到一個特定的詞的頻率在每個列表對於例如， 該系列產品是

0 [All, of, my, kids, have, cried, nonstop, when... 
1 [We, wanted, to, get, something, to, keep, tra... 
2 [My, daughter, had, her, 1st, baby, over, a, y... 
3 [One, of, babys, first, and, favorite, books, ... 
4 [Very, cute, interactive, book, My, son, loves... 

我想要得到每行孩子的數量。我曾嘗試

series.count('kids') 

這給了我一個錯誤說「級別的孩子必須是相同的名稱（無）」

series.str.count('kids) 

給我NaN值。

我應該如何去獲取計數？

Answer 1

使用

In [5288]: series.apply(lambda x: x.count('kids')) 
Out[5288]: 
0 1 
1 0 
2 0 
3 0 
4 0 
Name: s, dtype: int64 

---

詳細

In [5292]: series 
Out[5292]: 
0 [All, of, my, kids, have, cried, nonstop, when] 
1 [We, wanted, to, get, something, to, keep, tra] 
2 [My, daughter, had, her, 1st, baby, over, a, y] 
3  [One, of, babys, first, and, favorite, books] 
4 [Very, cute, interactive, book, My, son, loves] 
Name: s, dtype: object 

In [5293]: type(series) 
Out[5293]: pandas.core.series.Series 

In [5294]: type(series[0]) 
Out[5294]: list 

Answer 2

在原系列，使用str.findall + str.len：

print(series) 

0  All of my kids have cried nonstop when 
1  We wanted to get something to keep tra 
2  My daughter had her 1st baby over a y 
3  One of babys first and favorite books 
4 Very cute interactive book My son loves 

print(series.str.findall(r'\bkids\b')) 

0 [kids] 
1  [] 
2  [] 
3  [] 
4  [] 
dtype: object 

counts = series.str.findall(r'\bkids\b').str.len() 
print(counts) 

0 1 
1 0 
2 0 
3 0 
4 0 
dtype: int64