用Verilog聲明一個常量的數組

Question

首先我想爲我的無知道歉，這個問題可能對你們很多人來說都是愚蠢的。但是我是一個新手在Hw dev的域
我想把一個軟件功能到我們使用的整數來計算某一數值數組的C代碼硬件加速器... 如下所示

uint k[64] = { 
0x428a2f98,0x71374491,0xb5c0fbcf,0xe9b5dba5,0x3956c25b,0x59f111f1,0x923f82a4,0xab1c5ed5, 
0xd807aa98,0x12835b01,0x243185be,0x550c7dc3,0x72be5d74,0x80deb1fe,0x9bdc06a7,0xc19bf174, 
0xe49b69c1,0xefbe4786,0x0fc19dc6,0x240ca1cc,0x2de92c6f,0x4a7484aa,0x5cb0a9dc,0x76f988da, 
0x983e5152,0xa831c66d,0xb00327c8,0xbf597fc7,0xc6e00bf3,0xd5a79147,0x06ca6351,0x14292967, 
0x27b70a85,0x2e1b2138,0x4d2c6dfc,0x53380d13,0x650a7354,0x766a0abb,0x81c2c92e,0x92722c85, 
0xa2bfe8a1,0xa81a664b,0xc24b8b70,0xc76c51a3,0xd192e819,0xd6990624,0xf40e3585,0x106aa070, 
0x19a4c116,0x1e376c08,0x2748774c,0x34b0bcb5,0x391c0cb3,0x4ed8aa4a,0x5b9cca4f,0x682e6ff3, 
0x748f82ee,0x78a5636f,0x84c87814,0x8cc70208,0x90befffa,0xa4506ceb,0xbef9a3f7,0xc67178f2 
}; 

，你在這裏看到的是要去使用它來計算T1

$ t1 = h + EP1(e) + CH(e,f,g) + k[i] + m[i]; 

但是不是某些如何聲明這個數組而不使用寄存器，我有一個verilog文件，它使用localparam來聲明一個常量。所以我不知道我可以使用它與這個向量如下？

localparam [31:0] k[63:0] = 
{0x428a2f98,0x71374491,0xb5c0fbcf,0xe9b5dba5,0x3956c25b,0x59f111f1,0x923f82a4,0xab1c5ed5, 
0xd807aa98,0x12835b01,0x243185be,0x550c7dc3,0x72be5d74,0x80deb1fe,0x9bdc06a7,0xc19bf174, 
0xe49b69c1,0xefbe4786,0x0fc19dc6,0x240ca1cc,0x2de92c6f,0x4a7484aa,0x5cb0a9dc,0x76f988da, 
0x983e5152,0xa831c66d,0xb00327c8,0xbf597fc7,0xc6e00bf3,0xd5a79147,0x06ca6351,0x14292967, 
0x27b70a85,0x2e1b2138,0x4d2c6dfc,0x53380d13,0x650a7354,0x766a0abb,0x81c2c92e,0x92722c85, 
0xa2bfe8a1,0xa81a664b,0xc24b8b70,0xc76c51a3,0xd192e819,0xd6990624,0xf40e3585,0x106aa070, 
0x19a4c116,0x1e376c08,0x2748774c,0x34b0bcb5,0x391c0cb3,0x4ed8aa4a,0x5b9cca4f,0x682e6ff3, 
0x748f82ee,0x78a5636f,0x84c87814,0x8cc70208,0x90befffa,0xa4506ceb,0xbef9a3f7,0xc67178f2 
}; 

Answer 1

是的，你可以。但是，0x不是verilog語法，而是使用32'h（或只是'h，如果您希望它不太強類型）。

localparam logic [31:0] k[63:0] = 
{ 
32'h428a2f98,32'h71374491,32'hb5c0fbcf,32'he9b5dba5,32'h3956c25b,32'h59f111f1,32'h923f82a4,32'hab1c5ed5, 
32'hd807aa98,32'h12835b01,32'h243185be,32'h550c7dc3,32'h72be5d74,32'h80deb1fe,32'h9bdc06a7,32'hc19bf174, 
32'he49b69c1,32'hefbe4786,32'h0fc19dc6,32'h240ca1cc,32'h2de92c6f,32'h4a7484aa,32'h5cb0a9dc,32'h76f988da, 
32'h983e5152,32'ha831c66d,32'hb00327c8,32'hbf597fc7,32'hc6e00bf3,32'hd5a79147,32'h06ca6351,32'h14292967, 
32'h27b70a85,32'h2e1b2138,32'h4d2c6dfc,32'h53380d13,32'h650a7354,32'h766a0abb,32'h81c2c92e,32'h92722c85, 
32'ha2bfe8a1,32'ha81a664b,32'hc24b8b70,32'hc76c51a3,32'hd192e819,32'hd6990624,32'hf40e3585,32'h106aa070, 
32'h19a4c116,32'h1e376c08,32'h2748774c,32'h34b0bcb5,32'h391c0cb3,32'h4ed8aa4a,32'h5b9cca4f,32'h682e6ff3, 
32'h748f82ee,32'h78a5636f,32'h84c87814,32'h8cc70208,32'h90befffa,32'ha4506ceb,32'hbef9a3f7,32'hc67178f2 
}; 

Answer 2

你可能會更好用整數類型而不是localparam去。邏輯類型是4態，在模擬器上更貴，因爲你用它作爲一個常量值（我假設），你應該用整數來罰款。

integer k[64] = { 
32'h428a2f98,32'h71374491,32'hb5c0fbcf,32'he9b5dba5,32'h3956c25b,32'h59f111f1,32'h923f82a4,32'hab1c5ed5, 
32'hd807aa98,32'h12835b01,32'h243185be,32'h550c7dc3,32'h72be5d74,32'h80deb1fe,32'h9bdc06a7,32'hc19bf174, 
32'he49b69c1,32'hefbe4786,32'h0fc19dc6,32'h240ca1cc,32'h2de92c6f,32'h4a7484aa,32'h5cb0a9dc,32'h76f988da, 
32'h983e5152,32'ha831c66d,32'hb00327c8,32'hbf597fc7,32'hc6e00bf3,32'hd5a79147,32'h06ca6351,32'h14292967, 
32'h27b70a85,32'h2e1b2138,32'h4d2c6dfc,32'h53380d13,32'h650a7354,32'h766a0abb,32'h81c2c92e,32'h92722c85, 
32'ha2bfe8a1,32'ha81a664b,32'hc24b8b70,32'hc76c51a3,32'hd192e819,32'hd6990624,32'hf40e3585,32'h106aa070, 
32'h19a4c116,32'h1e376c08,32'h2748774c,32'h34b0bcb5,32'h391c0cb3,32'h4ed8aa4a,32'h5b9cca4f,32'h682e6ff3, 
32'h748f82ee,32'h78a5636f,32'h84c87814,32'h8cc70208,32'h90befffa,32'ha4506ceb,32'hbef9a3f7,32'hc67178f2 
};