大熊貓GROUPBY與datetimeindex

Question

grouped = data.groupby('LA_DECH') 
start = date(2016, 1, 1) 
end = date(2016, 12, 31) 
rng = pd.date_range(start, end, freq='BM') 

有一種簡單的方法來提取這一比較數據（DF列表）： '2016/1/1' < grouped['LA_DECH] < '2016/2/29'這對於在rng每個時期？

Answer 1

至少對我而言，你並沒有給出一個好的例子，你的問題是什麼，你想得到什麼。 你是指這個？

import pandas as pd 
import numpy as np 
from datetime import datetime 

start = datetime(2016,1,1) 
end = datetime(2016,12,31) 
idx = pd.date_range('2015-01-01','2017-09-01') 
df = pd.DataFrame(np.random.randint(10,size= (len(idx),2)), index= idx, columns=['VALUE',"LA_DECH"]) 

rng = pd.date_range(start, end, freq='BM') 
# filted by start and end date 
df = df[(df.index>start)&(df.index <end)] # this line is not necessary needed 
print(df.groupby([pd.cut(df.index,rng), 'LA_DECH'])['LA_DECH'].count()) 

           LA_DECH 
(2016-01-29, 2016-02-29] 0   2 
          2   1 
          3   5 
          4   2 
          5   3 
          6   4 
          7   4 
          8   5 
          9   5 
(2016-02-29, 2016-03-31] 0   4 
          2   1 
          3   4 
          4   5 
          5   2 
          6   3 
          7   3 
          8   6 
          9   3 

           .. 
(2016-08-31, 2016-09-30] 8   2 
          9   1 
(2016-11-30, 2016-12-30] 0   2 
          1   1 
          2   1 
          3   1 
          4   1 
          5   5 
          6   3 
          7   5 
          8   5 
          9   6 
Name: LA_DECH, Length: 104, dtype: int64