多繼承問題C++

Question

我有多重繼承問題。

#pragma once 
#include <iostream> 
#include <list> 
class Data { 
protected: 
    int year; 
    int month; 
    int day; 
public: 
    Data(); 
    Data(int, int, int); 
    void show(); 
}; 

class Person : virtual public Data { 
protected: 
    std::string Name; 
    std::string Sur_name; 
public: 
    Person(); 
    Person(std::string, std::string, int, int, int); 
    void show(); 
}; 

class Waiter : public Person { 
protected: 
    int category; 
public: 
    Waiter(); 
    Waiter(std::string, std::string, int d, int m, int y, int c); 
    void show(); 
}; 

class TypeOfDish { 
protected: 
    std::string typeDish; 
public: 
    TypeOfDish(); 
    TypeOfDish(std::string); 
    void show(); 
}; 

class Course : public TypeOfDish { 
protected: 
    double price; 
    std::string NameofCourse; 
public: 
    Course(); 
    Course(std::string, double, std::string); 
    void show(); 
}; 

class Order : public Course, public Waiter, virtual public Data{ 
public: 
    Order(); 
    void show(); 
}; 

////////////////////////////////////////

#include "stdafx.h" 
#include "Class.h" 
#include <string> 
Data::Data() { 
    day = 21; 
    month = 10; 
    year = 2017; 
} 
Data::Data(int d, int m, int y) { 
    this->day = d; 
    this->month = m; 
    this->year = y; 
} 

void Data::show() { 
    std::cout << "Hello from Data.Date of birth " << day << " " << month << " " << year << std::endl; 
} 

Person::Person() : Data() { 
    day = 22; 
    month = 10; 
    year = 2017; 
    Name = "Ivan"; 
    Sur_name = "Petrov"; 
} 

Person::Person(std::string n, std::string s, int d, int m, int y) : Data(d,m,y) { 
    this->Name = n; 
    this->Sur_name = s; 
} 

void Person::show() { 
    std::cout << "Hello from Person " << Name << " " << Sur_name << std::endl; 
    std::cout << "Hello from Person.Date of birth " << day << " " << month << " " << year << std::endl; 
} 

Waiter::Waiter() : Person() { 
    category = 3; 
} 
Waiter::Waiter(std::string n, std::string s, int d, int m, int y, int c) : Person(n,s,d,m,y) { 
    this->category = c; 
} 

void Waiter::show() { 
    std::cout << "Hello from Waiter " << Name << " " << Sur_name << std::endl; 
    std::cout << "Hello from Waiter.Date of birth " << day << " " << month << " " << year << std::endl; 
    std::cout << "Hello from Waiter.Category " << category << std::endl; 
} 

TypeOfDish::TypeOfDish() { 
    typeDish = ""; 
} 
TypeOfDish::TypeOfDish(std::string type) { 
    this->typeDish = type; 
} 
void TypeOfDish::show() { 
    std::cout << "The type of dish is " << typeDish << std::endl; 
} 

Course::Course() : TypeOfDish() { 
    price = 12.32; 
    NameofCourse = "Borsh"; 
} 

Course::Course(std::string name, double pri, std::string type) : TypeOfDish(type) { 
    this->NameofCourse = name; 
    this->price = pri; 
} 

void Course::show() { 
    std::cout << typeDish << ":" << NameofCourse << std::endl; 
} 

Order::Order() : Data(), Course(), Waiter() { 
    std::cout << "."; 
} 

void Order::show() { 
    std::cout << "Hello from Order " << Name << " " << Sur_name << std::endl; 
    std::cout << "Hello from Order.Date of birth " << Waiter::day << " " << Waiter::month << " " << Waiter::year << std::endl; 
    std::cout << "Hello from Order.Category " << category << std::endl; 
    std::cout << "Hello from Order.Date of order " << day << " " << month << " " << year << std::endl; 
    std::cout << "Hello from Order" << typeDish << ":" << NameofCourse << std::endl; 
} 

我有3個基本類 - 服務員，課程和數據及派生訂單。 我想從服務員，課程和數據中查看屏幕上的所有字段。 我的意思是姓名，姓氏，類別，出生日期從服務員，所有領域的課程也是最重要的訂單數據。 當我運行程序一切正常，但它不工作，我想要的方式。 出生日期和訂單日期的數據相同。

所以，我想知道我該如何解決這個問題。

任何解決方案將不勝感激。謝謝。

Answer 1

因爲您使用的是虛擬繼承，所以無論您是否使用範圍解析，您在Order實例中都只有一組日期 - 月份數據。

所以在Order :: show中，「Waiter :: day」和「day」指的是同一段數據。

如果要維護此結構，請刪除虛擬繼承，並且Order的每個實例都將包含單獨的Data實例;但請確保您也使用範圍解析來區分它們。

但是，我認爲你的繼承方案並不好。我不認爲命令「isa」課程或服務員;這應該是一個「hasa」關係，而不是從Course或Waiter繼承，Order應該包含這些類型的成員變量。