熊貓：字符串

Question

替換字符串我想在df

url 
icashier.alipay.com/catalog/2758186/detail.aspx 
icashier.alipay.com/catalog/2758186/detail.aspx 
icashier.alipay.com/catalog/2758186/detail.aspx 
vk.com 

更換子icashier.alipay.com在列aliexpress.com。

慾望輸出

aliexpress.com/catalog/2758186/detail.aspx 
aliexpress.com/catalog/2758186/detail.aspx 
aliexpress.com/catalog/2758186/detail.aspx 
vk.com 

我嘗試df['url'].replace('icashier.alipay.com', 'aliexpress.com', 'inplace=True')但它返回empty dataframe。

Answer 1

使用replace與dict更換和參數inplace=True和regex=True：

df['url'].replace({'icashier.alipay.com': 'aliexpress.com'}, inplace=True, regex=True) 
print (df) 
              url 
0 aliexpress.com/catalog/2758186/detail.aspx 
1 aliexpress.com/catalog/2758186/detail.aspx 
2 aliexpress.com/catalog/2758186/detail.aspx 
3          vk.com 

Answer 2

使用str.replace更換子，replace查找精確匹配，除非你傳遞一個正則表達式模式和param regex=True：

In [25]: 
df['url'] = df['url'].str.replace('icashier.alipay.com', 'aliexpress.com') 
df['url'] 

Out[25]: 
0 aliexpress.com/catalog/2758186/detail.aspx 
1 aliexpress.com/catalog/2758186/detail.aspx 
2 aliexpress.com/catalog/2758186/detail.aspx 
3          vk.com 
Name: url, dtype: object