使用Java中的方法實例變量？

Question

三角形方法有3個實例變量。 int side1，side2，side3;

他們給我我需要讓公衆三角法（INT S1，詮釋S2，INT S3）

不要我把它聲明爲：

public class triangle { 

private int s1; 
private int s2; 
private int s3; 

}

OR

public class triangle (int s1, int s2, int s3) { 

}

謝謝

我把這與混合了一個構造函數。想出來，謝謝你們。

Answer 1

public class triangle { 

    int s1; 
    int s2; 
    int s3; 

    public triangle (int s1, int s2, int s3) { 
     this.s1 = s1; 
     this.s2 = s2; 
     this.s3 = s3; 

    } 
} 

希望這會有所幫助。 謝謝

Answer 2

首先，如果方法名稱與類名稱相同，則它被稱爲constructor，當創建該類的新對象時調用該方法。

public class Triangle { 
    private int s1; // This are the private variable which 
    private int s2; // are accessed by only object of 
    private int s3; // class triagnle. 

    public class Triangle (int s1, int s2, int s3) // This is a constructor which is called 
    {            // when you create a object with new keyword 
     this.s1 = s1;        // like Triangle t = new Triangle(1,2,3); 
     this.s2 = s2; 
     this.s3 = s3; 
    } 
} 

Answer 3

最好的做法是

public class Triangle { 
//atributes 
private int s1; 
private int s2; 
private int s3; 

//encapsulation 
public int getS1() { 
     return s1; 
    } 
public int getS2() { 
     return s2; 
    } 
public int getS3() { 
     return s3; 
    } 
public void getS1(int value){ 
     this.s1 = value; 
    } 
public void getS2(int value){ 
     this.s2 = value; 
    } 
public void getS3(int value){ 
     this.s3 = value; 
    } 
//constructor 
public Triangle (int s1, int s2, int s3) 
{ 
    this.s1 = s1; 
    this.s2 = s2; 
    this.s3 = s3; 
    //do something 
} 
}