更多關於我的文字遊戲的問題

Question

while(!A){ 
      System.out.println ("You enter a room and look around, in it, you see three  doors, a red door labeled A, a blue door labeled B, and a green door labeled C. Which door do you choose to go through? Enter, A, B, or C"); 
      String correctdoor = scanner.next(); 

      A = "A".equalsIgnoreCase(correctdoor); 
      System.out.println("You have chosen wrong! You have fallen into a pit! Lucky for you though, the pit is easy to climb out of and you return to the room....\n\n\n");   
     } 

    System.out.println("You progress through the door and find 5 light switches, you must turn them on in order to progress further. Enter the correct combination (using digits 1-5) here please. HINT - the 2nd and 4th numbers add up to the first number and the last number is NOT 5"); 
    int lightcode = scanner.nextInt(); 
    while (!(lightcode == 31425)){System.out.println ("That combination is incorrect");} 
    System.out.println ("The door unlocks and you go down a set of stairs"); 

嘿，回來再尋求更多幫助。

當用戶輸入b或c或任何其他值不是A時，while語句的工作方式是按預期工作，但是當它們放入A時，它會將它們帶出while循環，但它仍然會打印出'您已選擇錯誤'的字符串。我不知道爲什麼，但我確定你們可以告訴我爲什麼。

此外，如果我輸入正確的數字，第二個循環完美工作，唯一的問題是，當我不這樣做，它會告訴我'組合不正確'，但它不會打印一次，它會一直打印它並不會停止，它的無休止的。我做錯了什麼？

也許我應該使用if語句？呃......不......那不會循環......呃。

PS我知道我說的最後一個數字的心不是5，但衣衫將其固定後

Answer 1

我看着你的代碼，並用此來了，它爲我工作和固定您所描述的問題：

現在

while(!A) 
{ 
     System.out.println ("You enter a room and look around, in it, you see three  doors, a red door labeled A, a blue door labeled B, and a green door labeled C. Which door do you choose to go through? Enter, A, B, or C"); 
     String correctdoor = scanner.next(); 

     A = "A".equalsIgnoreCase(correctdoor); 

     if (!A) // Added this here, displays the message only if they chose the incorrect door 
     { 
      System.out.println("You have chosen wrong! You have fallen into a pit! Lucky for you though, the pit is easy to climb out of and you return to the room....\n\n\n"); 
     } 
} 

，第二部分，這裏是我做的，這也是固定的，你所描述的問題：

int lightcode = 0; //Initialize lightcode to something incorrect here 
while (!(lightcode == 31425)) 
{ 
System.out.println("You progress through the door and find 5 light switches, you must turn them on in order to progress further. Enter the correct combination (using digits 1-5) here please. HINT - the 2nd and 4th numbers add up to the first number and the last number is NOT 5"); 
    lightcode = scanner.nextInt(); //Get lightcode from the player 

    if (!(lightcode == 31425)) //And finally, only if the code is INCORRECT, display the incorrect message 
    { 
    System.out.println ("That combination is incorrect"); 
    } 
} 

System.out.println ("The door unlocks and you go down a set of stairs"); 

Answer 2

好吧，這裏就是我會做這樣的：

while(true){ 
    System.out.println ("You enter a room and look around, in it, you see three  doors, a red door labeled A, a blue door labeled B, and a green door labeled C. Which door do you choose to go through? Enter, A, B, or C"); 
    String correctdoor = scanner.next(); 
    if("A".equalsIgnoreCase(correctdoor)) { 
    break; 
    } 
    System.out.println("You have chosen wrong! You have fallen into a pit! Lucky for you though, the pit is easy to climb out of and you return to the room....\n\n\n"); 
} 

我明白，intui！（lightcode == 31425）tively，在while循環中設置條件看起來像正確的路要走，但問題是，該條件是有用的，因爲你有流量控制發生在while循環中。所以，我只是更加清楚地說明了這一點：永久循環，如果correctdoor匹配「A」，就會打破循環

對於你的第二個問題，你可以使用非常相同的方法，因爲邏輯是一樣的：永遠循環直到你得到你的期望。

System.out.println("You progress through the door and find 5 light switches, you must turn them on in order to progress further. Enter the correct combination (using digits 1-5) here please. HINT - the 2nd and 4th numbers add up to the first number and the last number is NOT 5"); 
int lightcode = 0; 
while (true){ 
    lightcode = scanner.nextInt(); 
    if(lightcode == 31425) { 
    break; 
    } 
    System.out.println ("That combination is incorrect"); 
} 
    System.out.println ("The door unlocks and you go down a set of stairs"); 

如果你第一次要求每次重複鍵的聲明，就把它放在第二個開始的時候。 祝你的遊戲製作成功！ 爲了以防萬一，這裏有我寫的工作代碼的要點 https://gist.github.com/dallarosa/14617052520c571ad2ad